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2 years ago

Find the direction of this

Physics

1 answer:

Flauer [41]2 years ago

3 0

Answer:

42.8

Explanation:

subtract than divide by 2

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Four identical particles of mass 0.980 kg each are placed at the vertices of a 4.14 m x 4.14 m square and held there by four mas

Zielflug [23.3K]

Answer:

a) The rotational inertia when it passes through the midpoints of opposite sides and lies in the plane of the square is 16.8 kg m²

b) I = 50.39 kg m²

c) I = 16.8 kg m²

Explanation:

a) Given data:

m = 0.98 kg

a = 4.14 * 4.14

The moment of inertia is:

$I=mr^{2} \\r=\frac{a}{2} \\I=m(a/2)^{2} \\I=\frac{ma^{2} }{4}$

For 4 particles:

$I=4(\frac{ma^{2} }{4} )=ma^{2} =0.98*(4.14)^{2} =16.8kgm^{2}$

b) Distance from top left mass = x = a/2

Distance from bottom left mass = x = a/2

Distance from top right mass = x = √5 (a/2)

The total moment of inertia is:

$I=m(\frac{a}{2} )^{2} +m(\frac{a}{2} )^{2}+m(\frac{\sqrt{5a} }{2} )^{2}+m(\frac{\sqrt{5a} }{2} )^{2}=\frac{12ma^{2} }{4} =3ma^{2} =3*0.98*(4.14)^{2} =50.39kgm^{2}$

$I=2m(\frac{m}{\sqrt{2} } )^{2} =ma^{2} =0.98*(4.14)^{2} =16.8kgm^{2}$

8 0

3 years ago

I need help!!!! I don’t understand physical science at all.

allochka39001 [22]

B is the correct answer

3 0

3 years ago

A particle with charge +6.70 nC is in a uniform electric field directed to the left. Another force, in addition to the electric

mina [271]

Answer:

a) 4.6*10^{-5} J

b) 6133.33 J/C

c) 94358.9 C

Explanation:

(a) We have that the change in the kinetic energy equals the net work over the charge. Hence we have

$\Delta E_K=W-W_E$

where Ek is the kinetic energy, W is the work of the external force and WE is the work done by the electric field. By replacing we obtain:

$W_E=W-\Delta E_k=7.60*10^{-5}J-3*10^{-5}J=4.6*10^{-5}J$

(b) The potential difference is computed by using:

$\Delta V=\frac{W_E}{q}=\frac{4.6*10^{-5}J}{7.5*10^{-9}C}=6133.33\frac{J}{C}$

(c) With the work done by the electric force we can calculate the Electric field. By using the following formula we obtain:

$W_E=qEd\\\\E=\frac{W_E}{qd}=\frac{4.6*10^{-5}J}{(7.5*10^{-9}C)(6.50*10^{-2}m)}=94358.9\frac{N}{C}$

where we have used d=6.5cm=6.5*10^-9m and q=7.5nC=7.5*10^-9C

hope this helps!!

4 0

3 years ago

Read 2 more answers

Calculate the potential difference if 20J of energy are transferred by 8C of charge.

grin007 [14]

Explanation:

<h2>Given:</h2>

<h3>Energy = E = 20J</h3>

<h3>Charge = Q = 8C</h3>

<h2>Require :</h2>

___________

<h3>Potential Difference = V = ?</h3>

<h2>Formula :</h2>

____________

<h2>Solution:</h2><h3>_________</h3>

<h2> $\color{Red}{Mark - Brainliest}$ </h2>

4 0

3 years ago

How many electrons are shared between one nitrogen and one carbon atom

Fofino [41]

6 electrons are shared between a nitrogen and a carbon atom.

8 0

4 years ago