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natali 33 [55]
2 years ago
6

Find the direction of this

Physics
1 answer:
Flauer [41]2 years ago
3 0

Answer:

42.8

Explanation:

subtract than divide by 2

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A solenoid 0.425 m long has 950 turns of wire. What is the magnetic field in the center of the solenoid when it carries a curren
lesya692 [45]

Answer:

The magnetic field in the center of the solenoid is 7.8\times10^{-3}\ T.

Explanation:

Given that,

Length of solenoid = 0.425 m

Number of turns N = 950

Current I = 2.75 A

The magnetic field in the center of the solenoid is the product of the current , number of turns per unit length and permeability.

In mathematical form,

B = \mu_{0}nI

Where, n = \dfrac{N}{l}

N = number of turns

L = length

I = current

Now, The magnetic field

B = \dfrac{\mu_{0}NI}{l}

Put the value into the formula

B=\dfrac{4\pi\times10^{-7}\times950\times2.75}{0.425}

B=\dfrac{4\times3.14\times10^{-7}\times950\times2.75}{0.425}

B=7.8\times10^{-3}\ T

Hence, The magnetic field in the center of the solenoid is 7.8\times10^{-3}\ T.

4 0
3 years ago
PLEASE PLEASE HELP ME!
Vlad1618 [11]
B: heat is transferred as thermal energy by the interaction of moving particles
6 0
3 years ago
All objects emit what radiation
Eduardwww [97]
If an object is not at Absolute Zero, then it is
absorbing and radiating thermal (heat) energy.
5 0
3 years ago
A 65.0-Ω resistor is connected to the terminals of a battery whose emf is 12.0 V and whose internal resistance is 0.5 Ω. Calcula
Luda [366]

Answer:

a) 0.1832 A

b) 11.91 Volts

c) 2.18 Watt , 0.0168 Watt

Explanation:

(a)

R = external resistor connected to the terminals of the battery = 65 Ω

E = Emf of the battery = 12.0 Volts

r = internal resistance of the battery = 0.5 Ω

i = current flowing in the circuit

Using ohm's law

E = i (R + r)

12 = i (65 + 0.5)

i = 0.1832 A

(b)

Terminal voltage is given as

V_{ab} = i R

V_{ab} = (0.1832) (65)

V_{ab} = 11.91 Volts

(c)

Power dissipated in the resister R is given as

P_{R} = i²R

P_{R} = (0.1832)²(65)

P_{R} = 2.18 Watt

Power dissipated in the internal resistance is given as

P_{r} = i²r

P_{r} = (0.1832)²(0.5)

P_{r} = 0.0168 Watt

5 0
3 years ago
A rowboat passenger uses an oar to push the boat off the dock by exerting a force of 40N for 3.0s. What impulse acts on the boat
jarptica [38.1K]

Answer:

120 Ns

Explanation:

The impulse exerted on an object is given by:

I=Ft

where

F is the force applied

t is the time taken

In this problem, we have:

F = 40 N

t = 3.0 s

So, the impulse acting on the boat is

I=Ft=(40 N)(3.0 s)=120 Ns

8 0
3 years ago
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