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2 years ago

Find the direction of this

Physics

1 answer:

Flauer [41]2 years ago

3 0

Answer:

42.8

Explanation:

subtract than divide by 2

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Does a calculation lose any information when converted from centimeters to meters? Explain

german

Answer:

Explanation:

There are many units that are used to measure length of an object. For example centimeters, meters, millimeters etc.

There is a relationship between any of two units to measure lengths. If we want to convert some length from cm to m, it can be done as follows :

1 cm = 0.01 m

1 m = 100 cm

When we use this conversion, the calculation remains the same. Only the way to represent it will be different.

Hence, there is no lose of information when converted from centimeters to meters.

7 0

4 years ago

Two forces, F1 and F2 (with F1 > F2), act on an object of mass m. The two forces act along the same line but in opposite dire

natali 33 [55]

Here we can use Newton's II law to find the acceleration of the car

$F_{net} = ma$

here we know that

$F_{net} = F_1 - F_2$

as we know that two forces are equal in magnitude but opposite in direction so in order to find net force we need to subtract it

now from above equation

$F_1 - F_2 = ma$

$a = \frac{(F_1 - F_2)}{m}$

so here option A is correct

5 0

3 years ago

A bullet of mass 0.02 kg is fired by a gun of mass 20 kg. If the speed of the bullet is 150 ms -1,

wel

Answer:

0.15m/s

Explanation:

Momentum p = mv, must be conserved if there are no external forces acting on the system. Since there are only internal forces acting between the bullet and the gun, momentum must be conserved.

The total momentum before the gun is fired:

$p = m_{bullet}v_{bullet} + m_{gun}v_{gun} = 0.02 * 0 + 20 * 0 = 0$

The total momentum after the gun is fired, must also be zero:

$p = m_{bullet}v_{bullet} + m_{gun}v_{gun} = 0.02 * 150 + 20 * v_{gun} = 0$

Solving for v:

$v_{gun}=-\frac{m_{bullet}v_{bullet}}{m_{gun}} = -\frac{0.02*150}{20} =-0.15$

The recoil speed is the absolute value of the velocity.

7 0

3 years ago

Two point charges are brought closer together, increasing the force between them by a factor of 17. By what factor was their sep

nignag [31]

Answer:

$\dfrac{r_1}{r_2}=4.123$

Explanation:

Given:

Final force between them=17(initial force between them)

initial separation between them $r_1$

Final separation between them $r_2$

Let Q and q be the charges on them then

$F_2=17F_1\\\dfrac{kQq}{r_2^2}=17\dfrac{kQq}{r_1^2}\\\dfrac{r_1^2}{r_2^2}=17\\\dfrac{r_1}{r_2}=4.123$

6 0

3 years ago

Suppose that the Sun were to collapse from its current radius of about 700,000 km to a radius of only about 6000 km (about the r

Maksim231197 [3]

Answer:

Only there will be a change in density of sun.

Explanation:

As your question says only the radius of sun is decreased and there is no change in the mass. So it means that the center of gravity will be the same and as a result the gravitational force remains the same. Only the density of sun changes as it shrinks.

8 0

3 years ago

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