Explanation:
7) Given:
v₀ = 2.0 m/s
v = 0 m/s
t = 3.00 s
Find: Δx
Acceleration isn't included in the problem, so use a kinematic equation that doesn't involve a.
Δx = ½ (v + v₀) t
Δx = ½ (0 m/s + 2.0 m/s) (3.00 s)
Δx = 3.0 m
8) Given:
v₀ = 0 m/s
v = 5 m/s
t = 4 s
Find: a
Displacement isn't included in the problem, so use a kinematic equation that doesn't involve Δx.
v = at + v₀
5 m/s = a (4 s) + 0 m/s
a = 1.25 m/s²
9) Given:
v_avg = Δx / t
0.5 m/s = 8 m / t
t = 16 s
Answer:
1010713.18851 Pa
387999.259089 N
Explanation:
= Atmospheric pressure =
r = Radius = 2 m
h = Depth = 10 m
= Density of liquid methane =
g = Acceleration due to gravity = 7.44 m/s²
A = Area
Force is given by
The force exerted is 1010713.18851 Pa
The weight of the column of methane is 387999.259089 N
The pressure at a depth is given by
The pressure at the depth is
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