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sineoko [7]
3 years ago
14

How is sea salt harvested from the ocean? Name and explain the process.

Physics
1 answer:
mojhsa [17]3 years ago
7 0

Answer:

Sea salt is harvested by evaporating the ocean water away and generally has little to zero processing involved. Major sea salt manufacturers pump sea water into huge shallow “ponds” and allow the sun to evaporate the water... Before harvesting seawater, be sure the body of water you are using is not polluted.

Explanation:

hope it helps, please mark as brainliest

You might be interested in
An apple has a density of 641 kg/m3. Water has a
Vlad [161]

Answer:

D

Explanation:

Since the apple is 641kg/m3 and water is 1000kg/m3 then the apple will float. Light materials float on top of the water similar to how oil is always on top of the water layer. Since the two are close so the apple will partially float

6 0
3 years ago
An astronaut rides in a circular training accelerator at 16 m/s. If the radius of the accelerator is 8.0 meters, what is his cen
iren [92.7K]

Answer:

a=32\ m/s^2

Explanation:

Given that,

The velocity of an astronaut in a circular path, v = 16 m/s

The radius of the accelerator, r = 8 m

We need to find his centripetal acceleration. The formula that is used to find the centripetal acceleration is given by :

a=\dfrac{v^2}{r}\\\\a=\dfrac{(16)^2}{8}\\\\a=32\ m/s^2

So, the required centripetal acceleration is 32\ m/s^2.

7 0
3 years ago
A 0.350 kg block at -27.5°C is added to 0.217 kg of water at 25.0°C. They come to equilibrium at 16.4°C. What is the specific he
Gekata [30.6K]

The specific heat capacity of the block is 508J/kg^{\circ}C

Explanation:

As the block is placed into the water, heat energy is transferred from the water (which is at higher temperature) to the block (which is at lower temperature), until the block and the water are in thermal equilibrium (= same temperature).

Therefore, we can write:

Q_{water}=Q_{block}

Where

Q_{water}=m_w C_w (T_w-T_{eq}) is the heat energy released by the water, where

m_w = 0.217 kg is the mass of the water

C_w = 4186 J/kg^{\circ}C is the water heat specific capacity

T_w = 25.0^{\circ} is the initial temperature of the water

T_{eq}=16.4^{\circ} is the temperature at equilibrium

Substituting,

Q_{water}=(0.217)(4186)(25.0-16.4)=7812 J

Now we can write the heat energy absorbed by the block as

Q_{block}=m_b C_b(T_{eq}-T_b)

where

m_b=0.350 kg is the mass of the block

C_b is the specific heat capacity of the block

T_b = -27.5^{\circ} is the initial temperature of the block

And solving for C_b,

C_b=\frac{Q_{block}}{m_b(T_{eq}-T_b)}=\frac{7812}{(0.350)(16.4-(-27.5))}=508J/kg^{\circ}C

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

6 0
3 years ago
Can someone help with this question pls
morpeh [17]
I solved it and got 374.2N so i would put 375N

sorry i didn’t get any of the ones on there, i probably made a mistake.
6 0
3 years ago
What form of energy is most abundant on earth
Kipish [7]
Solar energy is the most abundant energy resource on earth.
4 0
4 years ago
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