Answer:
Explanation:
The <u>initial</u> vertical velocity is 540sin55° = 442.342103... 442 m/s
The <u>initial</u> horizontal velocity is 540cos55° = 309.731275... 310 m/s
In the real world, both initial velocities would be reduced by air resistance and vertical velocity will be altered by gravity.
Answer:
Vx = 35.31 [km/h]
Vy = 18.77 [km/h]
Explanation:
In order to solve this problem, we must decompose the velocity component by means of the angle of 28° using the cosine function of the angle.
![v_{x} = 40*cos(28)\\V_{x} = 35.31 [km/h]](https://tex.z-dn.net/?f=v_%7Bx%7D%20%3D%2040%2Acos%2828%29%5C%5CV_%7Bx%7D%20%3D%2035.31%20%5Bkm%2Fh%5D)
In order to find the vertical component, we must use the sine function of the angle.
![V_{y}=40*sin(28)\\V_{y} = 18.77 [km/h]](https://tex.z-dn.net/?f=V_%7By%7D%3D40%2Asin%2828%29%5C%5CV_%7By%7D%20%3D%2018.77%20%5Bkm%2Fh%5D)
Answer: is A
The acceleration of an object is determined by its mass and the net force acting on it.
Newton's second law says that "F=ma". what this means is that the force you apply to an object is equal to its mass times how fast it is accelerating.
Hope it helped.
The problem ask to calculate the bullet's flight time and the bullet's speed as it left the barrel. So base on the problem, the answer would be that the flight time is 0.076 seconds and the speed of the bullet is 657.9 m/s. I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications.
Answer:
OXYGEN
Explanation:brainlyist me
