PLEASE HELP ASAP!!!!! For the function f(x) = x2 + 3, what are the outputs for the inputs -3, 2, 0, and 5?

A cafe offers 3 sides with the lunch special. A customer can choose from rice, green beans, carrots, salad, and corn. How many d

elena-14-01-66 [18.8K]

12, because 3 times 4 is 12.

5 0

4 years ago

Read 2 more answers

two ships leave a port at the same time. the first ship sails on a bearing of 55° at 12 knots (natural miles per hour) and the s

Korvikt [17]

Answer:

37.59 nautical miles

Explanation:

Distance = Speed x Time

The speed of the first ship = 12 knots

Thus, the distance covered after 1.5 hours

$\begin{gathered} =12\times1.5 \\ =18\text{ miles} \end{gathered}$

The speed of the second ship = 22 knots

Thus, the distance covered after 1.5 hours

$\begin{gathered} =22\times1.5 \\ =33\text{ miles} \end{gathered}$

The diagram representing the ship's path is drawn and attached below:

The angle at port = 90 degrees.

The triangle is a right triangle.

Using Pythagorean Theorem:

$\begin{gathered} c^2=a^2+b^2 \\ c^2=18^2+33^2 \\ c^2=324+1089 \\ c^2=1413 \\ c=\sqrt[]{1413} \\ c=37.59\text{ miles} \end{gathered}$

The two ships are 37.59 nautical miles apart after 1.5 hours.

8 0

1 year ago

is 20% in a decimal 0.20 in fraction 20/50 54% is a 40 0.4 fraction 4/10 decimal percent 9% decimal 0.9 fraction 9/10 66% 0.66 6

Gre4nikov [31]

20% is .20/ 20/50 is 40% or .4 or 4/10/ 9% is .09 or 9/100 / 9/10 is 90% or .9/ 66% is .66 or 33/50 or 66/100/ 6/10 is 60% or 60/100 or .6/ 2% is .02 or 1/50 or 2/100. I didn't exactly understand the question, but I hope this answers your question.

7 0

3 years ago

Final exam scores are normally distributed with a mean of 74 and a standard deviation of 6. Approximately, what percentage of fi

notka56 [123]

Answer:

81.86%

Step-by-step explanation:

We have been given that final exam scores are normally distributed with a mean of 74 and a standard deviation of 6.

First of all we will find z-score using z-score formula.

$z=\frac{x-\mu}{\sigma}$

$z=\frac{68-74}{6}$

$z=\frac{-6}{6}=-1$

Now let us find z-score for 86.

$z=\frac{86-74}{6}$

$z=\frac{12}{6}=2$

Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,

$P(-1$