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2 years ago

PLEASE HELP ASAP!!!!! For the function f(x) = x2 + 3, what are the outputs for the inputs -3, 2, 0, and 5?

Mathematics

1 answer:

DaniilM [7]2 years ago

6 0

Switch the x for -3, 2, 0, and 5 so the answer will be B

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In a game of chance, two pyramid-shaped, four-sided dice (with sides 1, 2, 3, 4). one colored red and the other colored green, a

Soloha48 [4]

Answer:

0.25 or 25%

Step-by-step explanation:

There are 4 possible outcomes for each die, which gives us 16 possible combinations (4 x 4). In order for the sum to exceed 5, the possible outcomes are:

Red = 3, and Green = 3

Red = 3, and Green = 4

Red = 4, and Green = 3

Red = 4, and Green = 4

Therefore, the probability of winning on a single play is:

$P=\frac{4}{16}\\P=0.25$

The probability is 0.25 or 25%.

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2 years ago

The quotient of 2 and the sum of a number and 1

siniylev [52]

Answer:

2/(x + 1)

Step-by-step explanation:

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2 years ago

By October 19th, Gordon had read 35 pages. Starting on October 20th, he decides to read the same number of pages each day until

PilotLPTM [1.2K]

Gordon read a total of 35 pages, so if there is p pages read per day and 10 days you'd have something that looks like this: 35 = 10p.

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2 years ago

What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27

malfutka [58]

Answer with explanation:

$\rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}$

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0

3 years ago

Read 2 more answers

Cos30° cos45°-sin30° sin 45°

sammy [17]

Answer:

(√6 - √2)/4

Step-by-step explanation:

cos30°cos45° - sin30°sin45°

= cos (30 + 45)°

= cos 75°

= (√6 - √2)/4

4 0

2 years ago