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Olegator [25]
3 years ago
12

Combustion of Propane Gas

Chemistry
1 answer:
son4ous [18]3 years ago
8 0

Answer:

15

I may be wrong worked it out in my head

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You burn a 15g jellybean to warm 50 mL of water, which increases the temperature of the water 25 °C. How many calories of heat a
Juli2301 [7.4K]

Answer:

Q = 375\,cal

Explanation:

The quantity of heat transfered from the jellybean to the water is:

Q = \rho\cdot V \cdot c\cdot \Delta T

Q = \left(1\,\frac{g}{cm^{3}}\right)\cdot (15\,cm^{3})\cdot \left(1\,\frac{cal}{g\cdot ^{\circ} C} \right)\cdot (25\,^{\circ}C )

Q = 375\,cal

7 0
3 years ago
Read 2 more answers
Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).
SIZIF [17.4K]
5.20 mol C6H12* (84.2 g/mol C6H12)= 4.38*10^(2) g C6H12.

The answer should only have three significant figures, according to the numbers in the problem.

Hope this is helpful~
7 0
3 years ago
Solve an equilibrium problem (using an ice table) to calculate the ph of each solution: part a a solution that is 0.195 m in hc2
IrinaK [193]
To determine the pH of a solution which has 0.195 M hc2h3o2 and 0.125 M kc2h3o2, we use the ICE table and the acid dissociation constant of hc2h3o2 <span>to determine the concentration of the hydrogen ion present at equilibrium. We do as follows:

HC2H3OO = H+ + </span>C2H3OO-
KC2H3OO = K+ + C2H3OO-

Therefore, the only source of hydrogen ion would be the acid. We use the ICE table,
                    HC2H3OO           H+        C2H3OO-
I                     0.195                  0              0.125
C                      -x                    +x               +x
------------------------------------------------------------------
E                 0.195-x                x              0.125 + x

Ka = <span>1.8*10^-5 = (0.125 + x) (x) / 0.195 -x 
x = 2.81x10^-5 M = [H+]

pH = - log [H+]
pH = -log 2.81x10^-5
pH = 4.55

Therefore, the pH of the resulting solution would be 4.55.
</span>
4 0
3 years ago
Which mineral property is the least reliable for identifying a mineral?
earnstyle [38]
The answer is color as the least reliable
8 0
3 years ago
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What would be the new volume if the pressure on 600 mL is increased from 90 kPa to 150 kPa?
Karolina [17]

Explanation:

What would be the new volume if the pressure on 600 mL is increased from 90 kPa to 150 kPa? V = Pu V₂ = 360 mL ~ 400 mL 6.

6 0
3 years ago
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