Data Given:
Pressure = P = ?
Volume = V = 3.0 L
Temperature = T = 115 °C + 273 = 388 K
Mass = m = 75.0 g
M.mass = M = 44 g/mol
Solution:
Let suppose the Gas is acting Ideally. Then According to Ideal Gas Equation,
P V = n R T
Solving for P,
P = n R T / V ------ (1)
Calculating Moles,
n = m / M
n = 75.0 g / 44 g.mol⁻¹
n = 1.704 mol
Putting Values in Eq. 1,
P = (1.704 mol × 0.08205 atm.L.mol⁻¹.K⁻¹ × 388 K) ÷ 3.0 L
P = 18.08 atm
A concentrated acid<span> has a relatively large amount of solute dissolved in the solvent. A </span>dilute acid<span> has a relatively smaller amount of solute dissolved in the solvent. In a solution of a strong </span>acid<span> there would be solvated ions present, but no associated molecules present.</span>
Hey bro I’m a t2 high player looking
I will send link to the link to send link to the team server to send iconic compounds fr9m crystal and molies uses melodiphine
Answer:
Keq=0.866
Explanation:
Hello,
In this case, the undergone chemical reaction is:
In such a way, since 0.0055 mol of N₂O₄ remains in the flask, one infers that the reacted amount (
) was:
In addition, the produced amount of NO₂ is:
Finally, considering the flask's volume, the equilibrium constant is then computed as follows:
Best regards.
