Answer:
0.1828g/cm³
Explanation:
density= mass÷volume
m= 12.6g
v= 4.1×4.1×4.1 = 68.921cm³
•
density= 12.6÷68.921 = 0.1828g/cm³
1 mol = 6.02 * 10^23 atoms of carbon
x mol = 1.45 * 10^24 atoms of carbon
1/x =6.02*10^23 / 1.45 * 10^24
6.02 * 10^23 x = 1.45 * 10^24
x = 1.45 * 10^24 / 6.02 * 10^23
x = 2.41 mols of carbon
The atoms of the solid have to form a crystalline structure, which means that they have an ordered configuration that is the same throughout the entire solid.
Answer:
q = 38,5 kJ
Explanation:
In its melting point, at 0°C, water is liquid. The boiling point of water is 100°C. It is possible to estimate the heat you required to raise the temperature of water from 0°C to 100°C using:
q = C×m×ΔT
Where C is specific heat of water (4,184J/g°C), m is mass of water (92,0g) and ΔT is change in temperature (100°C-0°C = 100°C)
Replacing:
q = 4,184J/g°C×92,0g×100°C
q = 38493 J, in kilojoules:
<em>q = 38,5 kJ</em>
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I hope it helps!
Answer:
If 1000. mL of water freezes, which of the following is a reasonable approximation for the volume of the resulting ice?
Group of answer choices
1000. mL
961 mL
1040 mL
Explanation:
Ice is fewer denser than water.
The reason is the volume occupied by the same mass of ice with water is more than the volume occupied by water. Ice has more empty space within it.
Due to this reason, ice floats on water.
When 1000ml of water freezes to ice then its volume is greater than water.
Among the given options the correct answer is 1040 mL .
