To determine the pH of a solution which has 0.195 M hc2h3o2 and 0.125 M kc2h3o2, we use the ICE table and the acid dissociation constant of hc2h3o2 <span>to determine the concentration of the hydrogen ion present at equilibrium. We do as follows:
Therefore, the only source of hydrogen ion would be the acid. We use the ICE table, HC2H3OO H+ C2H3OO- I 0.195 0 0.125 C -x +x +x ------------------------------------------------------------------ E 0.195-x x 0.125 + x
Ka = <span>1.8*10^-5 = (0.125 + x) (x) / 0.195 -x x = 2.81x10^-5 M = [H+]
pH = - log [H+] pH = -log 2.81x10^-5 pH = 4.55
Therefore, the pH of the resulting solution would be 4.55.</span>