If the perimeter of a rectangle is 26x^2+16x+10 and the length is 8x^2+6x+4, what is the width?

Mathematics

2 answers:

dimaraw [331]3 years ago

7 0

Here is the set up:

P = 2L + 2W

P = 2(26x^2+16x+10) + 2(8x^2+6x+4)

Simplify the right side to find P.

Tanzania [10]3 years ago

7 0

Answer:

5x^2 + 14x + 9

To find the width, multiply the length that you have been given by 2, and subtract the result from the perimeter. You now have the total length for the remaining 2 sides. This number divided by 2 is the width.

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Consider the graph of the linear function h(x) = –6 + h(x) equals negative 6 plus StartFraction 2 Over 3 EndFraction x. x. Which

mel-nik [20]

Answer:

2nd quadrant.

Step-by-step explanation:

The given function is

$h(x)=-6+\dfrac{2}{3}x$

We need to find the quadrant from which the graph of function is not passing.

At x=0,

$h(0)=-6+\dfrac{2}{3}(0)=-6$

So, y-intercept is (0,-6).

At h(x)=0,

$0=-6+\dfrac{2}{3}x$

$6=\dfrac{2}{3}x$

$18=2x$

$9=x$

So, x-intercept is (9,0).

It means the graph intersect negative side of y-axis and positive side of x-axis. When we join these two points, we get the graph is not passing through the 2nd quadrant.

Therefore, the required quadrant is 2nd quadrant.