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3 years ago

If the perimeter of a rectangle is 26x^2+16x+10 and the length is 8x^2+6x+4, what is the width?

Mathematics

2 answers:

dimaraw [331]3 years ago

7 0

Here is the set up:

P = 2L + 2W

P = 2(26x^2+16x+10) + 2(8x^2+6x+4)

Simplify the right side to find P.

Tanzania [10]3 years ago

7 0

Answer:

5x^2 + 14x + 9

To find the width, multiply the length that you have been given by 2, and subtract the result from the perimeter. You now have the total length for the remaining 2 sides. This number divided by 2 is the width.

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Norma-Jean [14]

Answer:

556, 558, and 560

Step-by-step explanation:

1674/3 = 558 (An even number, yay)

So 558 + 558 + 558 = 1674

Subtract two from the first one and add two to the last (still equal)

556 + 558 + 560

adding them equals 1674 so the answer is

556, 558, and 560

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3 years ago

Read 2 more answers

H(x)=-(x+11)^2+1. What are the zeros of the function? What is the vertex of the parabola?

Nataly_w [17]

Answer:

x=-14

Step-by-step explanation:

-x-11^2+1

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