Answer:
0
Step-by-step explanation:
We are given the following vectors:
m = (a, b) = a<em>i</em> + b<em>j</em>
n = (c, d) = c<em>i</em> + d<em>j</em>
Values of a,b,c and d are given to be: a = 4, b = 4, c = 2, and d = −2
So, the vectors we have will be:
m = (4, 4) = 4<em>i</em> + 4<em>j</em>
n = (2, -2) = 2<em>i</em> - 2<em>j</em>
We need to find the magnitude of vector product m x m.
Remember that the vector(cross) product of a vector with itself is always 0. For any two vectors A and B, the magnitude of their vector(cross) product is defined as:
A x B = AB sin(θ)
Here, θ is the angle between two vectors A and B. if A and B represent the same vector then the angle θ will be zero. Since sin(θ) = 0, the magintude of the vector product will also be 0.
Therefore, for our question, the magnitude of the vector product m x m will be equal to 0.
