All categories

3 years ago

1. Which of the following is a solution to the

1 answer:

8 0

B. -25
The answer to X has to be negative. Since -2/5 is negative and we’re trying to get to 10, we need another negative to cancel out the negative into a positive. Multiply -2/5 by X (-25) so it’s -2/5 x -25/1. Negative times negative is positive. 2 x 25 is 50. 5 x 1 is 5. 50/5 is 10.

You might be interested in

The table shows the maximum and minimum depths of two submarines. Find the range of depths for each submarine. Then determine wh

JulsSmile [24]

Answer:

Range A = 386ft

Range B = 427ft

B has the larger range.

Explanation:

To find the range, find the difference between the minimum and maximum depths for each submarine. Remember that your answer will be positive.

Sub A:

-146ft - (-532ft) = 386 ft

Sub B:

-194ft - (-621ft) = 427 ft

Submarine B has a larger range.

7 0

3 years ago

Ok guys i have only 1 hr to get this. Determine the y-intercept for the equation 3x + 2y = 12. HELP

sukhopar [10]

Answer:

x= -2/3 y+4

Step-by-step explanation:

Let's solve for x.

3x+2y=12

Step 1: Add -2y to both sides.

3x+2y+−2y=12+−2y

3x=−2y+12

Step 2: Divide both sides by 3.

−2y+12

5 0

2 years ago

a local hamburger shop sold a combined total of 616 hamburgers and cheeseburgers on sunday. there were 66 moore cheeseburgers so

Ksju [112]

Answer:

242 Hamburgers, 374 Cheeseburgers

Step-by-step explanation:

Step 1: 616/2-66=242 Hamburgers

Step 2: 616-242=374 Cheeseburgers

Step 3: Check Work 242+374=616

4 0

2 years ago

-5 + 8 • -7 help lols

iris [78.8K]

Answer:

Step-by-step explanation:

-5 + (8 x -7)

using PEMDAS, (8 x -7) = -56

so -5 + -56 = -61

5 0

2 years ago

A random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength

irinina [24]

Answer:

Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.

Step-by-step explanation:

We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.

Let $\bar X$ = sample mean comprehensive strength

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean comprehensive strength = 5500 psi

$\sigma$ = standard deviation = 100 psi

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P( $\bar X$ > 4985 psi)

P( $\bar X$ > 4985 psi) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{4985-5500}{\frac{100}{\sqrt{9} } }$ ) = P(Z > -15.45) = P(Z < 15.45)

= 0.99999

Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.

4 0

3 years ago