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3 years ago

-5 + 8 • -7 help lols

Mathematics

1 answer:

iris [78.8K]3 years ago

5 0

Answer:

Step-by-step explanation:

-5 + (8 x -7)

using PEMDAS, (8 x -7) = -56

so -5 + -56 = -61

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ch4aika [34]

Answer:

Step-by-step explanation:

41+x=80

x=39

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3 years ago

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Rationalize the denominator !!!

satela [25.4K]

Answer:

$\frac{1\cdot \left(4+\sqrt{3}\right)}{\left(4-\sqrt{3}\right)\left(4+\sqrt{3}\right)}\\$

$1\cdot \left(4+\sqrt{3}\right)=4+\sqrt{3}$

$\left(4-\sqrt{3}\right)\left(4+\sqrt{3}\right) = 13$

$= \frac{4+\sqrt{3}}{13}$

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1 year ago

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Pythagorean Theorem:a2 + b2 = c2 Re−write the formula solving for b2 .

gulaghasi [49]

Answer: c2 - a2 = b2

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3 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

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3 years ago

Find the solution of y = 2x + 5 for x = 1.

Mumz [18]

Answer:

1.)

y = 2x + 5 for x = 1

y = 2(1) + 5

y = 2 + 5

y = 7

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TCP = $60 + $4(n)

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3 years ago