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James drove up 6,400 feet to a camp area on a mountain to meet his friends. They walked a trail that led to the mountain summit

gregori [183]

The answer is 4900 because you add the 6,400+1,800=8,200 then you subtract the 8,200-3,300= 4,900

6 0

3 years ago

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How to find median with even amount of numbers?

Paladinen [302]

Sort the numbers in ascending or descending order, then eliminate the greatest and least numbers until you're left with the middle two. The median is the average of the last two numbers.

For example, the median for the set $\{2,10,-1,4\}=\{-1,2,4,10\}$ is 3 because the middle two numbers are 2 and 4, and their average is $\dfrac{2+4}2=3$ .

8 0

3 years ago

A fair die is rolled 12 times. the number of times an even number occurs on the 12 rolls has

bonufazy [111]

Answer:

Step-by-step explanation:

For a fair die, there are six likely options; 1, 2, 3, 4, 5, and 6

the probability of a even number is 3/6 = 0.5

Since the results of the die roll is independent and each trial is mutually exclusive, the distribution to explain the probability of occurrence will follow a binomial distribution such that n is the number of trials

x = number of successful throws

therefore for a Binomial distribution where

P(X =x) = nCx . P^x . (1-P)^ (n-x)

since p = 0.5, and n = 12, the distribution follows

P(X = x) = 12Cx . 0.5^x . (1 - 0.5)^(12- x)

= 12Cx . 0.5^x . 0.5)^(12- x)

where x = (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)

since we are interested in the probability of the number of times an even number occurs

it can occur either as P(X = 0), P(X =1), P(X =2), P(X =3), P(X =4), P(X =5), P(X =6), P(X =7), P(X =8), P(X =9), P(X =10), P(X =11), and P(X =12)

For no even number in 12 rolls,

P(X = 0) = 12C0 . 0.5^0 . 0.5^(12- 0) = 0.000244

For one even number in 12 rolls,

P(X = 1) = 12C1 . 0.5^1 . 0.5^(12- 1) = 0.002930

For two even number in 12 rolls,

P(X = 2) = 12C2 . 0.5^2 . 0.5^(12- 2) = 0.016113

For three even number in 12 rolls,

P(X = 3) = 12C3 . 0.5^3 . 0.5^(12- 3) = 0.053711

For four even number in 12 rolls,

P(X = 4) = 12C4 . 0.5^4 . 0.5^(12- 4) = 0.120850

For five even number in 12 rolls,

P(X = 5) = 12C5 . 0.5^5 . 0.5^(12- 5) = 0.193359

For six even number in 12 rolls,

P(X = 6) = 12C6 . 0.5^6 . 0.5^(12- 6) = 0.225586

For seven even number in 12 rolls,

P(X = 7) = 12C7 . 0.5^7 . 0.5^(12- 7) = 0.193359

For eight even number in 12 rolls,

P(X = 8) = 12C8 . 0.5^8 . 0.5^(12- 8) = 0.120850

For nine even number in 12 rolls,

P(X = 9) = 12C9 . 0.5^9 . 0.5^(12- 9) = 0.053711

For ten even number in 12 rolls,

P(X = 10) = 12C10 . 0.5^10 . 0.5^(12- 10) = 0.016113

For eleven even number in 12 rolls,

P(X = 11) = 12C11 . 0.5^11 . 0.5^(12- 11) = 0.002930

For twelve even number in 12 rolls,

P(X = 12) = 12C12 . 0.5^12 . 0.5^(12- 12) = 0.000244

Final test summation[P(X)] = 1

i.e.

P(X = 0) + P(X =1) + P(X =2) + P(X =3) + P(X =4) + P(X =5) + P(X =6) + P(X =7) + P(X =8) + P(X =9) + P(X =10) + P(X =11) + P(X =12) = 1

Hence since 0.000244 + 0.002930 + 0.016113 + 0.053711 + 0.120850 + 0.193359 + 0.225586 + 0.193359 + 0.120850 + 0.053711 + 0.016113 + 0.002930 + 0.000244 = 1.000000,

the probability value stands

7 0

3 years ago

A pair of basketball shoes was originally priced at $80, but was marked up 47.5%. What was the retail

Lelu [443]

47.5% in decimal form is 0.475.

Since the price was increased, we add 1 to 0.475 to get 1.475.

80 * 1.475 = 118

Another way to solve this is to multiply 80 by 0.475, which is 38, then add it to 80.

The retail price of the shoes is $118.

6 0

3 years ago

Francesca is painting a picture of the purple flowers in her garden. She mixes paint to make the perfect color for each type of

aniked [119]

Find total ounces mixed for each flower:

Daisies = 2+5 = 7 ounces

Tulips = 3 +6 = 9 ounces

Now find the ratio of purple to white for each one:

Daisies = 5/7 = 0.714

Tulips = 6/9 = 0.666

Daisies have more purple so would be the darker ones.

8 0

2 years ago

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