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viva [34]
3 years ago
9

Jenny has some flowers in a bucket. She picks a flower at

Mathematics
1 answer:
saul85 [17]3 years ago
6 0

Answer:

Each flower is either red or yellow. Each flower is either a tulip or a rose. For these flowers number of tulips:number of roses 6 : 5.

Step-by-step explanation:

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A shirt is originally priced at $24.50 a shirt goes on sale for 30% off the original price how much money to the nearest cent do
Ainat [17]

Answer:

7.86 is the answer

Step-by-step explanation:

30% of 24.50 is 7.35.

7.35+ 7% is 7.86

7.86 to the nearest cent is 7.86

8 0
3 years ago
Solve a^3 • (-a^2b)^4
Varvara68 [4.7K]

Answer:/?idk

Step-by-step explanation:


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3 years ago
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D because it has to be a chord due to being perpendicular to a diameter
7 0
4 years ago
Find all solutions to the equation:
crimeas [40]

Let z = sin(x). This means z^2 = (sin(x))^2 = sin^2(x). This allows us to go from the equation you're given to this equation: 7z^2 - 14z + 2 = -5

That turns into 7z^2 - 14z + 7 = 0 after adding 5 to both sides. Use the quadratic formula to solve for z. The only solution is z = 1 (see attached image). Since we made z = sin(x), this means sin(x) = 1. All solutions to this equation will be in the form x = (pi/2) + 2pi*n, which is the radian form of the solution set. If you need the degree form, then it would be x = 90 + 360*n

The 2pi*n (or 360*n) part ensures we get every angle coterminal to pi/2 radians (90 degrees), which captures the entire solution set.

Note: The variable n can be any integer.

7 0
3 years ago
Write an equation for a circle with a diameter that has endpoints at (–10, 1) and (–8, 5). Round to the nearest tenth if necessa
satela [25.4K]

The standard form for the equation of a circle is :

<span><span><span> (x−h)^</span>2</span>+<span><span>(y−k)^</span>2</span>=<span>r2</span></span><span> ----------- EQ(1)
</span><span> where </span><span>handk</span><span> are the </span><span>x and y</span><span> coordinates of the center of the circle and </span>r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.

 So the midpoint of the diameter with endpoints at (−10,1)and(−8,5) is :

 ((−10+(−8))/2,(1+5)/2)=(−9,3)

 So the point (−9,3) is the center of the circle.

  Now, use the distance formula to find the radius of the circle:

  r^2=(−10−(−9))^2+(1−3)^2=1+4=5

 ⇒r=√5

 Subtituting h=−9, k=3 and r=√5 into EQ(1) gives :

 (x+9)^2+(y−3)^2=5

7 0
3 years ago
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