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Minchanka [31]
2 years ago
13

For what value of 0 is cos^-1(sqrt2/2)=0?

Mathematics
2 answers:
NeX [460]2 years ago
8 0

No Solution (i cant see the picture you attached but i can explain why.)

cos^-1(sqrt2/2)=0 is false

puteri [66]2 years ago
3 0

Answer:

B

Step-by-step explanation:

Edg2021

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If f(x) = –x2 + 3x + 5 and g(x) = x2 + 2x, which graph shows the graph of (f + g)(x)? On a coordinate plane, a straight line wit
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The graph of (f+g)(x) is on the coordinate plane, a straight line with a positive slope crosses the x-axis at (negative 1, 0) and crosses the y-axis at (0, 5).

<h3>What is the graph of a parabolic equation?</h3>

The graph of a parabolic equation is a curved U-shape graph from where the domain, the range, x-intercept(s), and the y-intercept(s) can be determined.

Given that:

f(x) = -x² + 3x + 5

g(x) = x² + 2x

To find (f + g)(x), we have:

(f + g)(x) = (-x² + 3x + 5)+(x² + 2x)

(f + g)(x) = -x² + 3x + 5 +x² + 2x

(f + g)(x) = 3x + 2x + 5

(f + g)(x) = 5x + 5

Use the Slope-intercept form: We are to find the graph of y = 5x + 5

y = 5x + 5

Here:

  • Slope = 5
  • x-intercept = (-1, 0)
  • y-intercept = (0,5)

Therefore, we can conclude that on the coordinate plane, a straight line with a positive slope crosses the x-axis at (negative 1, 0) and crosses the y-axis at (0, 5)

Learn more about parabolic equation here:

brainly.com/question/4061870

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4 0
2 years ago
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where would an imaginary line need to be drawn to reflect across an axis of symmetry so that a regular pentagon can carry onto i
irina [24]

Answer:

An imaginary line would need to be drawn at any angle to the center of the side opposite the angle to  reflect across an axis of symmetry so that a regular pentagon can carry onto itself. Hope this answer helps.

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an office supply company sells two types of printers. they charge $95 for one of the printers and $125 for the other. if the com
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Answer:

22 of the 95$ ones and 10 of the 125

Step-by-step explanation:

22 times 95 = 2090

10 times 125 = 1250

2090+1250=3340

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