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Minchanka [31]
3 years ago
13

For what value of 0 is cos^-1(sqrt2/2)=0?

Mathematics
2 answers:
NeX [460]3 years ago
8 0

No Solution (i cant see the picture you attached but i can explain why.)

cos^-1(sqrt2/2)=0 is false

puteri [66]3 years ago
3 0

Answer:

B

Step-by-step explanation:

Edg2021

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Answer:

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Step-by-step explanation:

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Find the GCF of -10c2d and 15 ca2
jonny [76]

Answer:

5c

Step-by-step explanation:

5c is the only value you can take out of both factors

4 0
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What is the answer for 6.8 6.9 6.10
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6 0
3 years ago
Possible solution for 4+x+2-2x=5
MrRissso [65]

Answer:

x=1

Step-by-step explanation:

For algebra always start by rewriting it.

4+x+2-2x=5

Then ask yourself is there any like terms we can combine, and here yes there is. 4 and 2 and x and -2x. Now lets combine them and rewrite.

6-x=5

Now lets get x alone and the quickest way is to subtract 6 to the other side

6-x=5

-6    -6

  -x=-1

Now the two negatives cancel out as you would divide both sides by the coefficient -1 to get positive x alone. We can make this easier by just canceling out the negatives.

Your answer is

x=1

3 0
3 years ago
Help me please !!!
Nat2105 [25]

Answer:

For 3x^2+4x+4=0

Discriminant= = -32

The solutions are

(-b+√x)/2a= (-2+2√-2)/3

(-b-√x)/2a= (-2-2√-2)/3

For 3x^2+2x+4=0

Discriminant= -44

The solutions

(-b+√x)/2a= (-1+√-11)/3

(-b-√x)/2a= (-1-√-11)/3

For 9x^2-6x+2=0

Discriminant= -36

The solutions

(-b+√x)/2a= (1+√-1)/3

(-b-√x)/2a= (1-√-1)/3

Step-by-step explanation:

Formula for the discriminant = b²-4ac

let the discriminant be = x for the equations

The solution of the equations

= (-b+√x)/2a and = (-b-√x)/2a

For 3x^2+4x+4=0

Discriminant= 4²-4(3)(4)

Discriminant= 16-48

Discriminant= = -32

The solutions

(-b+√x)/2a =( -4+√-32)/6

(-b+√x)/2a= (-4 +4√-2)/6

(-b+√x)/2a= (-2+2√-2)/3

(-b-√x)/2a =( -4-√-32)/6

(-b-√x)/2a= (-4 -4√-2)/6

(-b-√x)/2a= (-2-2√-2)/3

For 3x^2+2x+4=0

Discriminant= 2²-4(3)(4)

Discriminant= 4-48

Discriminant= -44

The solutions

(-b+√x)/2a =( -2+√-44)/6

(-b+√x)/2a= (-2 +2√-11)/6

(-b+√x)/2a= (-1+√-11)/3

(-b-√x)/2a =( -2-√-44)/6

(-b-√x)/2a= (-2 -2√-11)/6

(-b-√x)/2a= (-1-√-11)/3

For 9x^2-6x+2=0

Discriminant= (-6)²-4(9)(2)

Discriminant= 36 -72

Discriminant= -36

The solutions

(-b+√x)/2a =( 6+√-36)/18

(-b+√x)/2a= (6 +6√-1)/18

(-b+√x)/2a= (1+√-1)/3

(-b-√x)/2a =( 6-√-36)/18

(-b-√x)/2a= (6 -6√-1)/18

(-b-√x)/2a= (1-√-1)/3

6 0
3 years ago
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