An=a1r^(n-1)
given
a5=1/24
a10=1/768
we know that
a5=1/24=a1r^(5-1) and
a10=1/768=a1r^(10-1)
so
1/24=a1r^4
1/768=a1r^9
(a1r^9)/(a1r^4)=r^5=(1/768)/(1/24)=1/32
r^5=1/32
take 5th root of both sides
r=1/2
we have
a5=a1r^4=1/24
evaluate r^4 or (1/2)^4
1/16
a1(1/16)=1/24
times both sides by 16/1
a1=16/24
a1=2/3
the first term is 2/3
Answer:
p = -6
Step-by-step explanation:
1) Distribute 3 through the parenthesis {3p + 12 = p}
2) Subtract 12 from each side {3p = p - 12}
3) Subtract p from each side {2p = -12}
4) Divide each side by 2 {p = -6}
Answer:
0.7
Step-by-step explanation:
Glad to help :)
Answer: Dimensions of A are of length [L]
Dimensions of B are of 
Dimensions of C are of 
Step-by-step explanation:
The given equation is

Since the dimension on the L.H.S of the equation is [L] , each of the terms on the right hand side should also have dimension of length[L] to be dimensionally valid
Thus
Dimensions of A = [L]
Dimensions of Bt = [L]
![Bt=[L]\\\\](https://tex.z-dn.net/?f=Bt%3D%5BL%5D%5C%5C%5C%5C)
![[B][T]=[L]](https://tex.z-dn.net/?f=%5BB%5D%5BT%5D%3D%5BL%5D)
![\\\\\therefore [B]=LT^{-1}](https://tex.z-dn.net/?f=%5C%5C%5C%5C%5Ctherefore%20%5BB%5D%3DLT%5E%7B-1%7D)
Similarly
Dimensions of ![Ct^{}2 = [L]](https://tex.z-dn.net/?f=Ct%5E%7B%7D2%20%3D%20%5BL%5D)
![Ct^{2}=[L]\\\\[C][T]^{2}=[L]\\\\\therefore [C]=LT^{-2}](https://tex.z-dn.net/?f=Ct%5E%7B2%7D%3D%5BL%5D%5C%5C%5C%5C%5BC%5D%5BT%5D%5E%7B2%7D%3D%5BL%5D%5C%5C%5C%5C%5Ctherefore%20%5BC%5D%3DLT%5E%7B-2%7D)
S
Shsbsbshhdhdxdgdbdbdbhs
Step-by-step explanation:
Zndjhdhdhdhdhdhh