True
Because a negative square root is an i
Answer:

Step-by-step explanation:
<u>Roots of a polynomial</u>
If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

Where a is an arbitrary constant.
We know three of the roots of the degree-5 polynomial are:

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

Let's build up the polynomial, assuming a=1:

Since:


Operating the last two factors:

Operating, we have the required polynomial:

Answer: Answer= -23
Step-by-step explanation: plug in -5 for v. THen multiply 4 and -5 which should give you -20. then subtract -3 from -20 which will give you -23. :)
Answer:
x = 11/10
Step-by-step explanation:
5(2x - 1) = 6
Distribute
10x -5 = 6
Add 5 to each side
10x-5+5 = 6+5
10x = 11
Divide each side by 10
10x/10 = 11/10
x = 11/10
Its the first one A................