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2 years ago

28 pointss PLEASE HELP ISTG I ASKED THIS QUESTION 5 TIMES PLEASEEE WILL MARK BRAINLIEST

Mathematics

2 answers:

Shalnov [3]2 years ago

7 0

It’s true,true,false,false

Alexandra [31]2 years ago

5 0

Answer:

Step-by-step explanation:

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After diving 86 feet below the surface, a diver ascends at 4 feet per minute. After 12 minutes pass, where is the diver located

Gemiola [76]

One possible way:
-86+(4*12)=-38
-86 is the number where the diver is. 86 feet below the surface.
4*12 is the total number of feet he has ascended in 12 minutes.
Because he is ascending, so you add 4*12 (or 48) to -86.
The answer is -38, meaning he's 38 feet below the surface.

The diver is now 38 feet below the surface.

Hope this helps.

7 0

2 years ago

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

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2 years ago

Circle the equivalent expressions: A. 3(2p + 2) B. 12p C. p(3 + 3) + 6 D. 5p + 6 E. 2p + 4p + 6 F. 3 + 6p + 3

Anuta_ua [19.1K]

Answer:

a,e,f

Step-by-step explanation:

a. 6p+6

b.12p

c.6p

d.5p+6

e.6p+6

f.6p+6

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Makovka662 [10]

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