Given:
The given function is:
![f_1(x)=-3\cdot 2^{x-5}-4](https://tex.z-dn.net/?f=f_1%28x%29%3D-3%5Ccdot%202%5E%7Bx-5%7D-4)
The graph of the function is given.
To find:
The end behavior of the given function.
Solution:
We have,
![f_1(x)=-3\cdot 2^{x-5}-4](https://tex.z-dn.net/?f=f_1%28x%29%3D-3%5Ccdot%202%5E%7Bx-5%7D-4)
From the given graph it is clear that the function approaches to -4 at x approaches negative infinite and the function approaches to negative infinite at x approaches infinite.
as ![x\to -\infty](https://tex.z-dn.net/?f=x%5Cto%20-%5Cinfty)
as ![x\to \infty](https://tex.z-dn.net/?f=x%5Cto%20%5Cinfty)
Therefore, the end behaviors of the given function are:
as ![x\to -\infty](https://tex.z-dn.net/?f=x%5Cto%20-%5Cinfty)
as ![x\to \infty](https://tex.z-dn.net/?f=x%5Cto%20%5Cinfty)
First, we put a point at the vertex. Then, we extend a line upwards of slope 1/2 to the right of the vertex. Then extend a line upwards of slope -1/2 to the left of the vertex. This will give the graph of the equation.
9514 1404 393
Answer:
37°
Step-by-step explanation:
The diagonals of a rhombus are angle bisectors. Angle 1 matches the other half of angle L.
∠1 = 37°
__
Angle 2 is the complement, 53°, and angle 3 is the same as angle 2, 53°.
The diagonals of a rhombus are perpendicular bisectors of each other, so angle 4 is 90°.