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ozzi
3 years ago
9

A girl standing on a bridge throws a stone vertically downward with an initial velocity of 15.0 m/s into the river below. If the

stone hits the water 2.00 seconds later, what is the height of the bridge above the water
Physics
1 answer:
kirill115 [55]3 years ago
4 0

Answer:

the height of the bridge above the water is 49.6 m.

Explanation:

Given;

initial velocity of the stone, u = 15 m/s

time of motion of the stone, t = 2 s

The height of the bridge above the water is calculated from the following kinematic equation as follows;

h = ut + ¹/₂gt²

h = (15 x 2) + ¹/₂(9.8)(2²)

h = 30 + 19.6

h = 49.6 m

Therefore, the height of the bridge above the water is 49.6 m.

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