Answer:
∧·······∵·······∴·······Hello :D········∴·······∵·······∧
How is Mass or volume change affect density?: Density is an intensive property of the material or substance and depends upon the relationship between the mass and volume. Unless the mass changes in relation to the volume, the density will not change.
Are mass and volume related?: Mass and volume are two units used to measure objects. Mass is the amount of matter an object contains, while volume is how much space it takes up.We can say that the volume of the object is directly proportional to its mass. As the volume increases the mass of the object increases in direct proportion.
How can density of an object be determined?: If the mass of an object increases then its density increases because density is directly proportional to mass.
Hope this helped too. ~(;-;)~
Explanation:
<h2>Hope this helps! </h2><h2 />
The minimum speed of the particle is the Speed of light in glass is c/μ=2×108m/s.
<h3>Why is the refractive index important?</h3>
The higher the refractive index the slower the light travels, which causes a correspondingly increased change in the direction of the light within the material. What this means for lenses is that a higher refractive index material can bend the light more and allow the profile of the lens to be lower.
Refractive index values are usually determined at standard temperature. A higher temperature means the liquid becomes less dense and less viscous, causing light to travel faster in the medium.
To learn more about the refractive index visit the link
brainly.com/question/23750645
#SPJ4
Answer:
Explanation:
Diffraction grating is used to form interference pattern of dark and bright band.
Distance between adjacent slits (a ) = 1 / 420 mm
= 2.38 x 10⁻³ mm
2.38 x 10⁻⁶ m
wave length of red light
= 680 x 10⁻⁹ m
For bright red band
position x on the screen
= n λD / a , n = 0,1,2,3 etc
D = distance of screen
putting n = 1 , 2 and 3 , we can get three locations of bright red band.
x₁ = λD / a
= 680 x 10⁻⁹ x 2.8 / 2.38 x 10⁻⁶
= .8 m
= 80 cm
Position of second bright band
= 2 λD / a
= 2 x 80
= 160 cm
Position of third bright band
= 3 λD / a
= 3 x 80
= 240 cm
The question ask to find and calculate the induced current in the loop as a function time and the best answer would be that the induced current in the loop is 0.08 amperes. I hope you are satisfied with my answer and feel free to ask for more if you have clarifications and further questions
