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3 years ago

What would happen to an electric circuit if the current source was removed? Explain.

Physics

2 answers:

SIZIF [17.4K]3 years ago

7 0

Answer:

Im pretty sure if it was removed whatever what was working it would loose its power

Explanation:

mark me brainlist plz

Sonbull [250]3 years ago

6 0

If the power source was removed whatever it was running/charging would stop

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Three people are pushing a 500 kg of box in the same direction. applied forces are 30 n, 20 n, and 10 n respectively. if the acc

GREYUIT [131]

The total force applied by the three people is:
$F=30 N+20 N+10 N=60 N$
This force is pushing toward the direction of the motion, while the frictional force $F_f$ points in the opposite direction.
We can write Newton's second law applied to the block: the resultant of the two forces must be equal to the product between the block's mass and its acceleration
$F-F_f = ma$
We know the mass of the block, m=500 kg, and the acceleration, $a=0.02 m/s^2$ , so we can find the friction:
$F_f = F-ma=60 N - (500 kg)(0.02 m/s^2)=50 N$

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4 years ago

a wave's amplitude is 0.5 meters. if its amplitude is increased to 1 meter, how much does its energy change?

AfilCa [17]

The energy becomes 4 times greater.

5 0

3 years ago

3) 4 electrons are placed - one electron per corner - at the corners of a square of side 1 meter. One fixed proton is placed in

Eduardwww [97]

Explanation:

i believe that they are all going at 3.2 meters each, I did 4 times 0.8

4 0

3 years ago

If the normal force exerted by the track on the car when it is at the top of the track (point B) is 6.00 N , what is the normal

Eddi Din [679]

Answer:

So, the force, F is the agent which provides the basic property of motion or rest to the body.While, the car is more obviously to have a mass, m and that the angle withe road or surface is also given which is normal to the road(i.e angle =90 degree). Then we say that lets say that the car is moving with the constant velocity of 20 m/sec and its kept unchanged by the car. So, we have the mass, m as 1 kg for the car and the value of the gravity we have the g=9.8 m/sec.

Now,

We have F=ma,

and a=v/t,

so we can have another equation for it as,

Now, providing the required data to, it; ∴t =2 sec,

F=(1)×(20/2),

<u>F=10 N.</u>

So, the car would be acting the force,F of about 10 N while the car is present on the lower region of the track.

4 0

3 years ago

What do the arrows at point three indicate

Maru [420]

Maybe show a picture ? I don’t get the question .

5 0

3 years ago