I believe it is
1.6x=2.7(x-1.8)
1.1x=2.7*1.8
x~4.4
4.4*1.6
~7.1m
Answer:
force pushed the object = 10 × 5 = 50N
Answer:

Explanation:
Given:
- mass of solid disk,

- radius of disk,

- force of push applied to disk,

- distance of application of force from the center,

<em>For the condition of no slip the force of static friction must be greater than the applied force so that there is no skidding between the contact surfaces at the contact point.</em>

where:
= static frictional force




This is true since all matter contains some form of energy even just moving electrons and friction count as energy