Answer:
The vertical distance that the ski jumper fell is 417.45 m.
Explanation:
Given;
initial horizontal velocity of the jumper, = 26 m/s
horizontal distance of the jumper, dx = 240 m
The time of the motion is given by;
dx = Vₓt
t = dx / Vₓ
t = 240 / 26
t = 9.23 s
The vertical distance traveled by the diver is given by;
initial vertical velocity, , = 0
Therefore, the vertical distance that the ski jumper fell is 417.45 m.