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Answer:
The magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 1.01 x N/C
Explanation:
given information,
kinetic energy, KE = 3.25 x J
proton's mass, m = 1.673 x kg
charge, q = 1.602 x C
distance, d = 2 m
to find the electric field that will stop the proton, we can use the following equation:
E = F/q
= (KE/d) / q , KE = Fd --> F = KE/d
= KE/qd
= (3.25 x J) / (1.602 x
C)(2 m)
= 1.01 x N/C
Answer:
1.02 seconds
Explanation:
Initial velocity = u = 5 m/s
t = Time taken
s = Displacement travelled = 0
a = Acceleration due to gravity = -9.81 m/s² (negative sign due to direction)
Equation of motion
So, time taken to return to its initial position is 1.02 seconds