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AVprozaik [17]
3 years ago
11

What are the exact solutions of x2 − 3x − 1 = 0?

Mathematics
2 answers:
____ [38]3 years ago
7 0
Hi, the quadratic formula is: \boxed{X= \dfrac{-b \pm \sqrt{b ^{2}-4ac } }{2a}}

Values: a = 1; b = - 3; c = -1
Solving:

X ^{2}-3X-1=0

X= \dfrac{-(-3) \pm \sqrt{(-3) ^{2}-4(1)(-1) } }{2(1)}

X= \dfrac{3 \pm \sqrt{9+4} }{2}

X= \dfrac{3 \pm \sqrt{13} }{2}\ ===\ \textgreater \ \ Answer:\ \boxed{ \textbf{Option\ {C.}}}

GOOD LUCK...!!!
kobusy [5.1K]3 years ago
3 0
Option C is the answer!

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What is the tenth term in the sequence 9, 13, 17, 21, 25…?
Zinaida [17]

Answer:

45

Step-by-step explanation:

9, 13, 17, 21, 25

We are adding 4 each time

9+4 = 13

13+4 =17

17+4 = 21

The common difference =4

a1 = 9

The formula is

an = a1+d(n-1) where n is the term number

an = 9+4(n-1)

We want the 10th term

a10 = 9+4(10-1)

     = 9+4(9)

    = 9+36

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2 years ago
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harkovskaia [24]
Remark
I didn't know this was a calculus question. How dumb of me.

f(x + h) - f(x)
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7 0
3 years ago
How do you do this problem 7-r=8-r-r​
Oliga [24]

Answer:

r = 1

Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
Find the line through (3, 1, −2) that intersects and is perpendicular to the line x = −1 + t, y = −2 + t, z = −1 + t. (HINT: If
mel-nik [20]

Answer:

( xo , yo , zo ) = ( 1 , 0 , 1 )

Step-by-step explanation:

Given:-

- A line passing through point (3, 1, −2) intersects and is perpendicular to line with coordinates:

                  x = −1 + t, y = −2 + t, z = −1 + t   .... t = arbitrary parameter.

Find:-

The coordinates for point of intersection.

Solution:-

- The line that passes through point (3, 1, −2) = ( a, b , c ) and an a arbitrary point on the given line have the following direction vector d2 :

                 d2 = ( x2 , y2 , z2 )

                 x2 = a - ( x ) = 3 - ( -1 + t ) = 4 - t

                 y2 = b - ( y ) = 1 - ( -2 + t ) = 3 - t

                 z2 = c - ( z )  = -2 - ( -1 + t ) = -1 - t

                d2 = (  4 - t , 3 - t , -1 - t )

- The direction vector d1 of the given line is:

                 d1 = ( x1 , y1 , z1 )

                 x1 = 1

                 y1 = 1

                 z1 = 1

                 d1 = ( 1 , 1 , 1 )

- The dot product of two orthogonal vectors is always equal to zero:

                 d1.d2 = 0

                 (  4 - t , 3 - t , -1 - t ) . ( 1 , 1 , 1 ) = 0

- Solve for parameter (t):

                 (4 - t) + (3 - t) + (-1 - t) = 0

                  6 -3t = 0

                  t = 2  

- The coordinates of the point of intersections can be evaluated by substituting the value of "t" into the given equation of line:

                 xo ( t = 2) = - 1 + 2 = 1

                 yo ( t = 2) = - 2 + 2 = 0

                 zo ( t = 2) = - 1 + 2 = 1

- The coordinates are:

                 ( xo , yo , zo ) = ( 1 , 0 , 1 )

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bazaltina [42]

Answer:

Step-by-step explanation:

65% of 80 is

65*80/100=52

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3 years ago
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