Answer:
9) 128
10) 78
11) 31
12) 148
Step-by-step explanation:
9) we know that the segment across from the angle 48° is double the angle.
48 · 2 = 96
The segments around the circle should all add up to 360 so we add the two segments we know to find the unknown segment.
136 + 96 = 232
360 - 232 = 128
The answer for 9 is 128.
10)
61 + 80 = 141
180 - 141 = 39
39 * 2 = 78
The answer for question 10 is 78.
11)
236 + 62 = 298
360 - 298 = 62
62 ÷ 2 = 31
The answer for question 11 is 31.
12)
50 · 2 = 100
100 + 112 = 212
360 - 212 = 148
The answer for question 12 is 148.
Divide both sides by 8.25
to get h=25
plz mark by the brainiest and thanks plz
The amount in gallons of each milk containing 9% butterfat and milk containing 4% butterfat which must be used to obtain the desired 365 gallons are;
- 219 gallons of 9% fat.
- 146 gallons of 7% fat.
<h3>What quantity of each type of milk is required for the desired 365 gallon?</h3>
It follows from the task content that the quantity of each type of milk required to arrive at the targeted fat content and quantity of milk are to be determined.
Let x = quantity of 9% fat milk and
Let y = quantity of 4% fat milk
Therefore, by mass balance; we have;
x + y = 365.
Where; y = 365 - x.
Also, by fat balance; we have;
(9% × x) + (4% × y) = (7% × 365)
9x + 4y = 2555
Therefore, the two equations to be solved simultaneously by substituting y from the first equation into the second equation as follows;
9x + 4 (365 - x) = 2555
5x = 1095
x = 1095/5
x = 219 gallons.
Also, y = 365 - 219 = 146 gallons.
Read more on simultaneous equations;
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Answer:
67.38°
Step-by-step explanation:
The diagonals of a rhombus intersect at their midpoints and make a right angle. They also divide the angles of the rhombus in two equal angles.
So, to find the acute angle of the rhombus, we can use the tangent relation of half this angle in the small triangle made when drawing the diagonals:
tan(angle/2) = 4 / 6
tan(angle/2) = 0.666
angle/2 = 33.69
angle = 67.38°
So the acute angle of the rhombus is 67.38 degrees.
Please check the image attached for better comprehension.
Answer:
x=7 and y=2
Step-by-step explanation:
In this case, you want to use elimination
1. multiply the second equation by -1
5x + 3y = 41
2x + 3y = 20
turns into
5x + 3y = 41
-2x + 3y = 20
2. combine the equations
3x=21
3. solve for x
3x=21
3x/3=21/3
x=7
4. Now you want to plug x back into the original equation
5x+3y=41
turns into
5(7)+3y=41
5. Then solve for y
35+3y=41
35+3y-35=41-35
3y=6
3y/3=6/3
y=2
6. results
x=7 and y=2
