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Elenna [48]
3 years ago
11

24

Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

2n-4

Step-by-step explanation:

it isn't actually lololololol reeeeèeee. Nah jk it is

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Find the solution to the differential equation dz/dt = 7te^4z that passes through the origin.
andreev551 [17]

Answer:

z=(\frac{-1}{4} )ln|1-14t^{2}|\\

Step-by-step explanation:

from the equation, \frac{dz}{dt}=7te^{4z}\\.

we can give different approach to the equation, but to make it simple and direct, let separate the equation by bringing all like terms to the same side i.e

\frac{dz}{e^{4z}}=7tdt\\e^{-4z} dz=7tdt.

if we integrate both side,

\int\limits^a_b{e^{-4z} } \,dz =\int\limits^a_b {7t} \,dt

-1/4e^{-4z} +c_{1}=7/2t^{2} +c_{2}\\-1/4e^{-4z}= 7/2t^{2} +c_{2}-c_{1}\\let c_{2}-c_{1}=c \\-1/4e^{-4z}= 7/2t^{2} +c

since the equation passes through the origin, and at the origin z=0 and t=0

we substitute this values and solve for the constant c

e^{-4*0}= 7/2*0 +c\\c=1.

If we substitute the value of c into the equation we arrive at

(-1/4)e^{-4z}= (7/2)t^{2}+1\\ e^{-4z}=1-14t^{2} \\

if we the the natural logarithm of both sides, we arrive at

-4z=ln|1-14t^{2}|\\z=(\frac{-1}{4} )ln|1-14t^{2}|\\

3 0
3 years ago
I need to know if there is a square root for 233
sashaice [31]
There is no square root for 233
5 0
3 years ago
In the equation below, what is the coefficient of the variable?
qaws [65]
B

but i have to write more to let me post this so here it is




7 0
3 years ago
Someone pls help me!!!!
tresset_1 [31]

Answer:

C.

Step-by-step explanation:

1 X 26 = 26

2 X 26 = 52

3 X 26 = 78

how is tat algebra???

7 0
3 years ago
F(x) = x^2 + 5x - 1 is shifted 3 units left the result is g(x). What is g(x)?
Sonja [21]

Answer:

A. g(x)=x^2+5x+2

Step-by-step explanation:

f(x) = x^2 + 5x - 1 Shift 3 units to the left. k=3

g(x)=x^2+5x-1+3=x^2+5x+2

g(x)=x^2+5x+2

Hope this helps!

If not, I am sorry.

5 0
2 years ago
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