A, B, C, E, and F
A because 2 and 6 are on the parallel line
B because 2 and 7 are alternate exterior angles
C because 4 and 8 are on the parallel line
E because 3 and 6 are alternate interior angles
F because 3 and 7 are on the parallel line
Answer:
The applicant need a score of at least 481.25.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the percentile of this measure.
In this problem, we have that:
The mean quantitative score on a standardized test for female college-bound high school seniors was 350. The scores are approximately Normally distributed with a population standard deviation of 75. This means that .
A scholarship committee wants to give awards to college-bound women who score at the 96th percentile or above on the test. What score does an applicant need?
This score is the value of X when Z has a pvalue of 0.96.
Looking at the z score table, we find that Z has a pvalue of 0.96 at . So
The applicant need a score of at least 481.25.
(-1,-2) would result in a relation that is no longer a function.
In the table, there's already x = -1 and y = -4. Function only gives a single y-value with x-value. If a single x-value gives two y-values then it'd not be Function.
If we add (-1,-2) in the table. The domain will be repetitive. Basically, we already have (-1,-4) and if we add (-1,-2) in the table, a single x-value will give TWO y-values which is not a function.
Answer:
3
Step-by-step explanation:
Factors of 15: 1, 3, 5, 15
Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24
Between these to factors only 1 and 3 is same factors and 3 is the greatest.
SO the GCF is 3.