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! What are modern numbers? and how are they used?

Cerrena [4.2K]

Modern numbers are the ten numerical digits used in constructing other numbers.

<h3>What are modern numbers?</h3>

Modern numbers are also called Arabic numerals. They are the ten numerical digits:

0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.

Uses of modern numbers;

They are used as symbols to write decimal numbers.
They are used in writing numbers in other systems like the octal, and for writing identifiers such as computer symbols, trademarks, or license plates.
They are used in constructing other numbers.

Hence, modern numbers are the ten numerical digits used in constructing other numbers.

Learn more about modern numbers here:

https://brainly.in/question/20910128

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7 0

2 years ago

4x^2-y^2+80x+16y+272=0

Andrew [12]

Answer:

$\frac{4x + 40}{-y +8}$

Step-by-step explanation:

8 0

4 years ago

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo

muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: $P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}$

Where $\lambda$ is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

$P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}$

Substitute the respective values in the above formula.

$P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})$

$P(k > 2)= 1 - (0.44596)$

$P(k > 2)=0.55404$

Hence, the required probability is 0.55404.

4 0

3 years ago

Find slope intercept form of 5x+8y=120 passing through (4,5)

yarga [219]

Answer:

$y=-(5/8)x+(15/2)$ or $y=-0.625x+7.5$

Step-by-step explanation:

The question is

Find the slope intercept form of the line parallel to the line 5x+8y=120 passing through (4,5)

step 1

Find the slope of the given line

we have

$5x+8y=120$

isolate the variable y

$8y=-5x+120$

$y=-(5/8)x+15$

The slope of the given line is m=-5/8

step 2

Find the slope of the line parallel to the given line

we know that

If two lines are parallel, then their slopes are the same

so

The slope of the parallel line to given line is m=-5/8

step 3

Find the equation of the line into slope intercept form

The equation of the line into slope intercept form is equal to

$y=mx+b$

we have

m=-5/8 and point (4,5)

substitute and solve for b

$5=-(5/8)(4)+b$

$b=5+(20/8)$

$b=60/8=15/2=7.5$

substitute

$y=-(5/8)x+(15/2)$

or

$y=-0.625x+7.5$

5 0

4 years ago

Roger can run one mile in 8 minutes. jeff can run one mile in 6 minutes. if jeff gives roger a 1 minute head start, how long wi

Anastasy [175]

Recall your d = rt, distance = rate * time.

now, if Roger can do 1 mile in 8 minutes, so in 1 minute, he has done then 1/8 of a mile, so his rate is 1/8 miles per minute.

if Jeff can do 1 mile in 6 minutes, he's faster, in 1 minute he has done 1/6 of a mile, so his rate is 1/6 miles per minute.

now, when Jeff catches up with Roger, the distance covered by both will be the same, say "d" miles, because, at that millisecond, Jeff will be neck and neck with Roger, and their covered distance will be the same.

now, Jeff is generous and let Roger roll on for 1 minute before him, so, by the time time Roger has covered "d" miles, he has been running for say "t" minutes.

however, since Jeff started later by 1 minute, he hasn't been running for "t" minutes, but for "t - 1" minutes.

$\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mpm}{rate}&\stackrel{minutes}{time}\\
&------&------&------\\
Roger&d&\frac{1}{8}&t\\\\
Jeff&d&\frac{1}{6}&t-1
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=\frac{1}{8}t\\\\
d=\frac{1}{6}(t-1)\\
------\\
\boxed{\frac{1}{8}t}=\cfrac{t-1}{6}
\end{cases}
\\\\\\
\cfrac{t}{8}=\cfrac{t-1}{6}\implies 6t=8t-8\implies 8=2t\implies \cfrac{8}{2}=t\implies \boxed{\stackrel{mins}{4}=t}$

4 0

3 years ago