Answer:
Step-by-step explanation:
Solve the quadtdd atic function (x + 1)2 = 16
1 answer:
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Answer:
- 0.83
- 0.9
- steeper than
- slower than
Step-by-step explanation:
Letting t=1 in Ted's equation, we find that he climbs 5/6 stairs in 1 second. As a decimal, 5/6 ≈ 0.83.
Michael climbs 9 stairs in 10 seconds so his rate is ...
... (9 stairs)/(10 seconds) = (9/10) stairs/second = 0.9 stairs/second
Michael's graph will be a line with a slope of 0.9; Ted's graph will be a line with a slope of about 0.83, so the line on Michael's graph is steeper.
Ted climbs fewer stairs per second, so his rate is slower than Michael's.
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<em>Comment on the problem</em>
You're being asked to compare two different rates that are associated with two different people. First the comparison is one way, then it is the other way. This can be confusing. It might be helpful to draw and label a simple chart to help you keep it straight. (The attachment is such a chart scribbled on a bit of scratch paper. It is sufficient for the purpose.)
Answer:
(a) NULL HYPOTHESIS, :
3.5%
ALTERNATE HYPOTHESIS, :
> 3.5%
(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.
Step-by-step explanation:
We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.
We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.
(a) Let, NULL HYPOTHESIS, :
3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}
ALTERNATE HYPOTHESIS, :
> 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}
The test statistics that will be used here is One-sample t-test;
T.S. = ~
where, = sample mean debt ratio of Ohio banks = 6%
s = sample standard deviation = = 1.83%
n = sample of banks = 7
So, test statistics = ~
= 3.614
(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.
Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.
Hence, Federal banking officials claim was correct.