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Julli [10]
2 years ago
15

1) Write a unit rate for the situation: 50 students in 5 classes

Mathematics
2 answers:
LUCKY_DIMON [66]2 years ago
8 0

Answer:

10 students per class

Step-by-step explanation:

Ede4ka [16]2 years ago
5 0

Answer:

10 students per class

Brainiest plz? :)

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Can someone help me with this? thanks
Sergio039 [100]

Answer:

least to greatest:

-11.7   -11.4   20/40  11.6

6 0
3 years ago
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Plzzzzz help Me I'm not smart
MAVERICK [17]

Answer:

(3X8) - 4 + 2 - 12

Step-by-step explanation:

Following the order of operations solve:

(24) - 4 + 2 - 12

20 + 2 - 12

22 - 12

10

Don't feel bad, this is an odd question and the parenthesis do not seem to be required. Following the order of operations would result in the same answer anyway...

Odd.

3 0
3 years ago
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Help Por favor! Will mark brainliest!
postnew [5]

Answer: An adult’s ticket costs $9 while a children’s ticket costs $5.

Step-by-step explanation:

1). 2x + 3y = 33

2). 5x + 2y = 55

3). I’m going to use substitution.

Isolate a variable (x):

2x + 3y = 33

2x = -3y + 33

X = (-3y + 33)/2

X = -3/2y + 33/2

Substitute and solve for y:

5x + 2y = 55

5(-3/2y + 33/2) + 2y = 55

-15/2y + 165/2 + 2y = 55

-11/2y = -55/2

Y = 5 <— children’s ticket.

Solve for x:

2x + 3y = 33

2x + 3(5) = 33

2x + 15 = 33

2x = 18

X = 9 <— adult’s ticket.

Check:

5x + 2y = 55

5(9) + 2(5) = 55

45 + 10 = 55

55 = 55

2x + 3y = 33

2(9) + 3(5) = 33

18 + 15 = 33

33 = 33

8 0
3 years ago
Guys 20 points please helpppp​
Igoryamba

Answer:

i would say your right

Step-by-step explanation:

8 0
3 years ago
Simplify this step by step<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B-5jk%7D%7B35j%5E2k%5E2%7D%20" id="TexFormula1" tit
VikaD [51]
\frac { -5jk }{ 35{ j }^{ 2 }{ k }^{ 2 } } \\ \\ =-\frac { 5 }{ 35 } \cdot \frac { j }{ { j }^{ 2 } } \cdot \frac { k }{ { k }^{ 2 } } \\ \\ =-\frac { 1 }{ 7 } \cdot \frac { 1 }{ j } \cdot \frac { 1 }{ k } \\ \\ =-\frac { 1 }{ 7jk }

Remember that:

\frac { j }{ { j }^{ 2 } } =\frac { 1 }{ j } \cdot \frac { j }{ j } =\frac { 1 }{ j } \cdot 1=\frac { 1 }{ j } \\ \\ \frac { k }{ { k }^{ 2 } } =\frac { 1 }{ k } \cdot \frac { k }{ k } =\frac { 1 }{ k } \cdot 1=\frac { 1 }{ k }
8 0
3 years ago
Read 2 more answers
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