Answer:
d.
Step-by-step explanation:
To convert a root to a fraction in the exponent, remember this rule:
![\sqrt[n]{a^{m}}=a^{\frac{m}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%7D%3Da%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D)
The index becomes the denominator in the fraction. (The index is the little number in front of the root, "n".) The original exponent remains in the numerator.
In this question, the index is 4.
The index is applied to every base in the equation under the root. The bases are 16, 'x' and 'y'.
![\sqrt[4]{16x^{15}y^{17}} = (\sqrt[4]{16})(\sqrt[4]{x^{15}})(\sqrt[4]{y^{17}}) = (2)(x^{\frac{15}{4}}})(y^{\frac{17}{4}}) = 2x^{\frac{15}{4}}}y^{\frac{17}{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16x%5E%7B15%7Dy%5E%7B17%7D%7D%20%3D%20%28%5Csqrt%5B4%5D%7B16%7D%29%28%5Csqrt%5B4%5D%7Bx%5E%7B15%7D%7D%29%28%5Csqrt%5B4%5D%7By%5E%7B17%7D%7D%29%20%3D%20%282%29%28x%5E%7B%5Cfrac%7B15%7D%7B4%7D%7D%7D%29%28y%5E%7B%5Cfrac%7B17%7D%7B4%7D%7D%29%20%3D%202x%5E%7B%5Cfrac%7B15%7D%7B4%7D%7D%7Dy%5E%7B%5Cfrac%7B17%7D%7B4%7D%7D)
To find the quad root of 16, input this into your calculator. Since 2⁴ = 16, ![\sqrt[4]{16}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D)
= 2.
For the "x" and "y" bases, use the rule for converting roots to exponent fractions. The index, 4, becomes the denominator in each fraction.
Answer:
where −5 ≤ x ≤ 3
Step-by-step explanation:
The given function is 
.
We want to select the option that describes all the solutions to the parabola.
The domain of the parabola is −5 ≤ x ≤ 3.
This means that any x=a on −5 ≤ x ≤ 3 that satisfies (a,f(a)), is a solution.
This can be rewritten as 
Therefore for x belonging to −5 ≤ x ≤ 3, all solutions are given by:
where −5 ≤ x ≤ 3.
Answer:
5+3a=29
Step-by-step explanation:
let Ella's age be 'a'
Vicki's age=5+2a
sum of their ages= 29
So, the equation is
(5+2a)+a=29
5+3a=29
<em>hope this helps!</em>
27 divided by 3 (j) is 9. If j=3 then plug in 3 for the equation
Answer:
(2,-9)
Step-by-step explanation:
Set the quadratic equal to zero.
Factor
Set each of these factors to zero
and
and
Plot the midpoint of the two values.
So the middle term is 2 and the other terms are 5 and -1.
Now the vertex is
So the vertex is
(2,-9)
