Here, we are required to determine after how many minutes will the two substances be at the same temperature.
The equation of when the two substances will be at the same temperature and the solution are as follows;
(a) The equation is 96.2 + 1.5(x) = 98.5 + 0.8(x).
(b) The solution is, x = 3.285minutes.
For substance A which is currently at 96.2° and rising at 1.5° each minute; It's temperature after x minutes is given as;
For substance B which is currently at 98.5° and rising at 0.8° each minute; It's temperature after x minutes is given as;
(a) For the two substances to be at the same temperature; T(a) must be equal to T(b).
The equation is therefore;.
96.2 + 1.5(x) = 98.5 + 0.8(x)
(b) To determine the solution;
1.5x - 0.8x = 98.5 - 96.2
0.7x = 2.3
x = 2.3/0.7
x = 3.285minutes.
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1 is the answer to your question hope this helps
Answer: 1
These are vertical angles so they are equal so
6a + 11 = 2a + 83
now solve for a
There are five significant figures in 12.001
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:
where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:
Hence, the half life of the sample of phosphorus-32 is
