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1 answer:
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The nth term is
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is
a1=1
r=2
we want to find
(since we minus 1, the highest exponet is 9 so add 1 to make it correct)
an=a1(r)^(n-1)
an=1(2)^(n-1)
a1=1
r=2
the sum of a geometric seequence is
a1=1
r=2
we want to find
See the attached picture for 2 options for question 1 and 2 depending on how the fractions are written.
Question #3:
17 = -13 - 8x
Add 13 to each side:
30 = -8x
Divide both sides by -8:
X = 30 / -8
X = -3 3/4
