Answer:
the top one
because identity of addition is adding 0
Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
Your description and expansion suggest you want to evaluate
.. 246₈ = 2*8² +4*8¹ +6*8⁰
.. = 2*64 +4*8 +6
.. = 166
Answer:
y= -3x/5
Step-by-step explanation:
y=mx+b where m is the slope and b is the y-intercept
m= rise/run = -3/5 (go from one point to the other on the graph)
y-intercept is (0,0)
