Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
I think the answer is A.33 not a polunomial
Yes it can be in fractions and in decimals
hi,
you must replace x by the number between parenthese.
I show you with the first one and let you do the second one
p(x) = 11x^5 -11x^4 - 5x^2 +15x-8
p(-4) = 11 (-4)^5 - 11 (-4)^4 -5(-4)² +15(-4) -8
p(-4) = 11 ( -1024- 256) - 5*16 -60-8
p(-4) = 11 ( -1280) -80-60-8
p(-4) = - 14080 - 148
p(-4) = - 14 228
Answer:
Fish Population The population of a certain species of fish has a relative growth rate of 1.2 %per year. It is estimated that the population in 2000 was 12 million. (a) Find an exponential model for the population tyears after 2000 . (b) Estimate the fish population in the year 2005 (c) Sketch a graph of the fish population.
Step-by-step explanation:
