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OLga [1]
3 years ago
12

Whats the is distance between (-9, 1) and (-9, 6)

Mathematics
2 answers:
Nadya [2.5K]3 years ago
6 0
4 cubic squares is the answer
Anettt [7]3 years ago
6 0

Answer:

d=(x2-x1)^2 + (y2-y1)^2

this is the distance formula...

Points: (-9,1) and (-9,6)

d=(-9-(-9))^2 + (6-1)^2

d=(0)^2 + (5)^2

d=0+25

d=25

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Step-by-step explanation:

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3 years ago
Square lMNO is shown in the diagram below what are the coordinates of the midpoint of a diagonal LN
sashaice [31]

Answer:

The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

answer (4)

Step-by-step explanation:

* Lets explain how to find the midpoint of a line

- The coordinates of the midpoint of a line whose endpoints are (x1 , y1)

 and (x2 , y2) are x=\frac{x_{1}+x_{2}}{2},y=\frac{y_{1}+y_{2}}{2}

∵ LMNO is a square

∵ The coordinates of point L are (-6 , 1)

∵ The coordinates of point N are (1 , 8)

- Let the coordinates of point L are (x1 , y1) , the coordinates of point

 N are (x2 , y2) and the coordinates of the midpoint of LN are (x , y)

∴ x1 = -6 , x2 = 1 and y1 = 1 , y2 = 8

- Use the rule of the midpoint above to find the midpoint (x , y)

∵ x=\frac{-6+1}{2}=\frac{-5}{2}=-2\frac{1}{2}

∵ y=\frac{1+8}{2}=\frac{9}{4}=4\frac{1}{2}

∴ The coordinates of the midpoint are (-2\frac{1}{2},4\frac{1}{2})

* The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

8 0
3 years ago
Which of the following is equivalent to 1/3(6x-12y) ?
harkovskaia [24]
1/3(6x-12y)
2x - 4y

the answer is A
5 0
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