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Brilliant_brown [7]
3 years ago
12

Simplify: 2 (5 + 3x) + (x + 10)

Mathematics
1 answer:
IgorLugansk [536]3 years ago
6 0
10 + 15x + x + 10
= 16x + 20
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What is the scale factor in the dilation if the coordinates of A prime are (–7, 6) and the coordinates of C prime are (–4, 3)?
olchik [2.2K]

Option A: \frac{1}{3} is the dilation factor

Explanation:

The Coordinates of the square ABCD are A(-21,18), B(-12,18), C(-12,9), D(-21,9)

Also, the coordinates of the square A'B'C'D' are A'(–7, 6), B'(-4,6), C'(-4,3), D'(-8,3)

Now, we shall determine the scale factor in the dilation if the coordinates A' and C'.

Since, the dilation is the enlargement of the image in the same shape but different size.

To determine the scale factor, let us divide A'C' by AC

Thus, we have,

\begin{aligned}A^{\prime} C^{\prime} &=\sqrt{(-4+7)^{2}+(3-6)^{2}} \\&=\sqrt{3^{2}+(-3)^{2}} \\&=\sqrt{9+9} \\&=\sqrt{18}\\&=3\sqrt{2} \end{aligned}

Also,

\begin{aligned}A C &=\sqrt{(-12+21)^{2}+(9-18)^{2}} \\&=\sqrt{9^{2}+(-9)^{2}} \\&=\sqrt{81+81} \\&=\sqrt{162}\\&=9\sqrt{2} \end{aligned}

Dividing A'C' by AC, we have,

\frac{A'C'}{AC} =\frac{3\sqrt{2} }{9\sqrt{2}} =\frac{1}{3}

Thus, \frac{1}{3} is the dilation factor

3 0
3 years ago
Read 2 more answers
How do i get x 0.15x+45=150
crimeas [40]
Subtract 45 on each side so it would be
0.15X=104 then divide both sides by 0.15X

then X= 700
3 0
2 years ago
Which data is considered a out liner 40,35, 44,90,23,25,28,35
lana66690 [7]
90 is the outlier
for future reference, outliers are numbers much larger or much smaller than the other numbers in a set
for example
2,3,4,21,6
or 90,87,94,12,99
7 0
3 years ago
WILL GIVE BRAINLIEST! NEED ANSWER FAST!
yuradex [85]

Answer:

x= 251

Step-by-step explanation:

300x= 190x + 27,610

300x-190x= 27,610

110x= 27610

x= 27610/110

x= 251

3 0
3 years ago
W is greater than -1 and less than or equal to 4<br> Use a only once in your inequality.
Mice21 [21]

Answer:

-1 + w ≤ 4

Step-by-step explanation:

w is greater than -1 = -1 + w

Less than or equal to 4 = (anything less than or equal to 4)≤4

7 0
2 years ago
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