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3 years ago

he yearbook club had a meeting. The meeting had 24 people, which is three-fourths of the club. How many people are in the club

Mathematics

1 answer:

WINSTONCH [101]3 years ago

4 0

Answer:

32 people

Step-by-step explanation:

If 3/4 equals 24, we need to find the other fourth. We can divided the total number of people by the numerator. 24/8, then add 8, which equals 32.

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What is 35 divide by 573

mrs_skeptik [129]

35 divided by 573 is 0.0610820244328098

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3 years ago

What is the value of -5.872 + (-5.1) ÷ 1.5? (a.) -9.272 (b.) -2.472 (c.) -7.315 (d.) 0.515

BigorU [14]

Answer:

The answer is A) -9.272

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2 years ago

Find an equation of the tangent line to the graph of

lakkis [162]

Answer:

y + 4 = -3 (x - 5)

In other words,

y = -3 x + 11

Step-by-step explanation:

The slope of the tangent line to y = g(x) at x = 5 is the same as the value of g'(x). g'(5) = 3. Therefore, 3 will be the slope of the tangent line.

The tangent line goes through the point of tangency (5, g(5)). g(5) = -4. Therefore, the tangent line passes through the point (5, -4).

Apply the slope-point form of the line. The equation for a line with slope <em>m</em> that goes through point (a, b) will be y - b = m(x - a). For the tangent line in this question,

m = 3,
a = 5, and
b = -4.

What will be the equation of this line?

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3 years ago

Read 2 more answers

Jesse takes his dog and cat for their annual vet visit.Jesse's dog weighs 23 pounds.The vet tells him his cat's weight is 5/8 as

Kobotan [32]

If I’m not mistaken the cats weight is 14.4

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3 years ago

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

4 0

3 years ago