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noname [10]
3 years ago
11

What is the arc length if θ = 7 pi over 4 and the radius is 5?

Mathematics
2 answers:
PolarNik [594]3 years ago
4 0

The formula for arc length is:

s= r∅

Given that ∅= 7π/4

and r= 5

Therefore, arc length s= 7π/4 *5 = 35π/4

jarptica [38.1K]3 years ago
4 0

Answer:  The required arc length will be 27.5 units.

Step-by-step explanation:  We are given to find the arc length with the following information :

\theta=\dfrac{7\pi}{4},~~~\textup{radius},~r=5.

We know that the length of an arc with angle subtended at the center α and radius of the circle r units is given by

\ell=r\alpha.

Therefore, the required arc length will be

\ell=r\theta=5\times\dfrac{7\pi}{4}=\dfrac{35}{4}\times \dfrac{22}{7}=\dfrac{5\times 11}{2}=\dfrac{55}{2}=27.5.

Thus, the required arc length will be 27.5 units.

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A triangle has sides with lengths of 18 centimeters, 68 centimeters and 74 centimeters. Is it a right triangle?
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18^2 + 68^2 =

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The 95% confidence interval of the population mean, in years, is (4.3, 5.3). 4 years is not part of the confidence interval, which means that it contradicts the fact that 39% of students get their college degree in four years.

-----------------------------

To solve this question, we need to find the confidence interval for the amount of time it takes the students to get the degree.

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

-----------------------------

The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So

df = 80 - 1 = 79

-----------------------------

95% confidence interval

Standard level of confidence, we have to find a value of T, which is found looking at the t table, with 79 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.9905.

-----------------------------

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9905\frac{2.2}{\sqrt{80}} = 0.5

In which s is the standard deviation of the sample and n is the size of the sample.

-----------------------------

The lower end of the interval is the sample mean subtracted by M. So it is 4.8 - 0.3 = 4.3 years.

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-----------------------------

The 95% confidence interval of the population mean, in years, is (4.3, 5.3). 4 years is not part of the confidence interval, which means that it contradicts the fact that 39% of students get their college degree in four years.

A similar question is given at brainly.com/question/24278748

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Using a z-distribution calculator, it is found that the p-value associated for a r<em>ight-tailed test with z = 2.115</em> is of 0.0172, hence, this is significant at the 5% level, but not at the 1% level.

More can be learned about p-values at brainly.com/question/16313918

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