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Effectus [21]
3 years ago
14

If 2/3 X – 1= 4, then x =

Mathematics
1 answer:
Alik [6]3 years ago
8 0

Answer: \frac{15}{2}

Step-by-step explanation:

\frac{2}{3}x-1=4

\frac{2}{3} x=4+1

\frac{2}{3} x=5

x=\frac{5}{\frac{2}{3} } =\frac{\frac{5}{1} }{\frac{2}{3} } =\frac{5*3}{1*2} =\frac{15}{2}

x=\frac{15}{2}

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Leona [35]
The answer to your question is 15.6
5 0
3 years ago
Solve for the following equation for the given variable 24= -2(4t-4)
lys-0071 [83]

Answer:

88

Step-by-step explanation:

6 0
3 years ago
If x + 5y = -11 and 2x − 3y = 17, what is the value of x + y?
aev [14]
X+5y=-11 (1)
2x-3y=17 (2)

2(1)-(2)
2x+10y-2x+3y=-22-17
13y=-39
y=-3

Sub y=-3 in (1)
x+5(-3)=-11
x=4

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6 0
3 years ago
Notice that the alternative hypothesis is a two-tailed test. Suppose ttest_ind method from scipy module is used to perform the t
Korvikt [17]

Answer:

The <em>p</em>-value of the test is 0.0512.

Step-by-step explanation:

The <em>p</em>-value of a test is well-defined as per the probability, [under the null hypothesis (H₀)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic.

In this case the output of the t-test_ind method from scipy module is provided as follows:

Output = (-1.99, 0.0512)

The first value within the parentheses is the test statistic value.

So the test statistic value is, -1.99.

And the second value within the parentheses is the <em>p</em>-value of the test.

So the <em>p</em>-value of the test is 0.0512.

6 0
3 years ago
Find the volume of this sphere.<br> Use 3 for TT.<br> V V ~ [?]cm3<br> V = nr3<br> r=6cm
Katen [24]

Answer:

V = 864cm^3

Step-by-step explanation:

Given

r = 6

\pi = 3

Required

The volume of the sphere

This is calculated as:

V = \frac{4}{3} \pi r^3

So, we have:

V = \frac{4}{3} *3 *6^3

V = \frac{4}{3} *3 *216

This gives:

V = 4 *216

V = 864

6 0
3 years ago
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