On average, people visit Thrillville 2 more times per year than Funland.
<h3><u>Averages</u></h3>
To determine how many more times per year, on average, do people visit Thrillville than Funland, the following calculation must be performed:
- Funland: 4,1,2,1,5,6,3,2,4,3,2,6,1,3,2 = 45
- 45 / 15 = 3
- Thrillville: 8,6,5,7,2,5,4,2,1,9,3,8,3,7,5,2,9,4,2,8 = 100
- 100 / 20 = 5
- 5 - 3 = 2
Therefore, on average, people visit Thrillville 2 more times per year than Funland.
Learn more about averages in brainly.com/question/2426692
13.95+2.25+2.25+2.25+2.75+2.75+2.75= 28.95
<span>Given:
Net profit before tax = $208,000
Total equity = $500,000
Total assets = $330,000
Total liabilities = $150,000
Current assets = $64,000
Current liabilities= $45,000
Return on Equity = Net Income / Shareholder's equity = 208,000 / 500,000 = 0.416 or 41.6%.
Return on Assets = Net Income / Total Assets = 208,000 / 330,000 = 0.63 or 63%
Debt ratio = Total Liabilities / Total Assets = 150,000 / 330,000 = 0.4545 or 45.45%
Debt to equity ratio = Total liabilities / Total Equity = 150,000 / 500,000 = 0.30 or 30%
Current ratio = Current Assets / Current Liabilities = 64,000 / 45,000 = 1.42</span>
Answer:
48 ways
Step-by-step explanation:
Let me take a guess
S₁_₁₅ = (1+15)*7 + 8 = 120
There are 48 combinations of distinct digits from 1 to 15 to make 20
120-20=100
So every 20 has a corresponding 100
I wish I got it right, otherwise report it.
We need to find two numbers that multiply to 24 (last coefficient) and add to 10 (middle coefficient). Through trial and error, the two values are 6 and 4
6 + 4 = 10
6*4 = 24
So we can break up the 10ab into 6ab+4ab and then use factor by grouping
a^2 + 10ab + 24b^2
a^2 + 6ab + 4ab + 24b^2
(a^2+6ab) + (4ab+24b^2)
a(a+6b) + 4b(a+6b)
(a+4b)(a+6b)
Therefore, the original expression factors completely to (a+4b)(a+6b)
