Answer:Yes i do
Step-by-step explanation:
Your welcome :)
Answer:
Step-by-step explanation:
22) J(2,-1); K(2,5)
Distance = √(x₂-x₁)² + (y₂-y₁)²
= √( 2- 2)² + (5 - [-1] )²
= √0 + (5 + 1 )²
=√ ( 6 )² = 6
25) A(0,3) ; B (0,12)
distance =√(0-0)² + (12 - 3 )²
=√( 9)² = 9
28) Q(12,-12) ; T(5,12)
distance = √(5 - 12)² + (12 - [-12] )²
= √( -7)² + (12 + 12] )²
= √ 49 + (24)²
= √ 49 + 576
= √625
=25
Answer:
(2, 8) and (3, 11) --- > For example
Step-by-step explanation:
Plug in any number for x
I will use 2.
So if the equation is y = 3x + 2, then the new equation will be ...
y = 3(2) + 2
y = 6 + 2
y = 8 ----> One coordinate can be (2, 8)
Another number you could use is 3.
y = 3(3) + 2
y = 9 + 2
y = 11 ----> Another coordinate may be (3, 11)
Answer:
The answer to your question is below
Step-by-step explanation:
See the graph below
Process
1.- Find the distance from A to B, B to C, C to D, A to D
Formula
d = 
d AB = 
dBC = 
dCD = 
dAD = 
2.- Find the perimeter
Perimeter = 2
= 
u
3.- Find the area
Area = 
Area = 
