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3 years ago

An oak dresser has a volume of 0.1cubic meters and a mass of 90kilograms. Calculate its density.

Mathematics

2 answers:

Mars2501 [29]3 years ago

8 0

Answer:

900kg/ $m^{3}$

Step-by-step explanation:

Formula: d = m/v

Given: m = 90, v = 0.1

Sub: d = 90/0.1

Solve: d = 900

Kipish [7]3 years ago

7 0

The answer is 900kg/m^3

Hope this helps good luck

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nevsk [136]

The equivalent sets are <u>X n Y = { } and X U Y= {5, 6, 7,8, 9, 10, 12 ,14}</u>

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Y = {5, 6, 7, 8,9}

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2 years ago

The service life of a battery used in a cardiac pacemaker is assumed to be normally distributed. A random sample of ten batterie

Fittoniya [83]

Answer:

The confidence interval is $25.16 < \mu < 26.85$

Step-by-step explanation:

From the question we are given a data set

25.5, 26.1, 26.8, 23.2, 24.2, 28.4, 25.0, 27.8, 27.3, and 25.7.

The mean of the this sample data is

$\= x = \frac{\sum x_i}{n}$

where is the sample size with values n = 10

$\= x = \frac{25.5+ 26.1+ 26.8+23.2+ 24.2+ 28.4+ 25.0+ 27.8+ 27.3+ 25.7}{10}$

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$\sigma = \sqrt{\frac{\sum (x-\= x)}{n} }$

substituting values

$= \sqrt{\frac{ ( 25.5-26)^2, (26.1-26)^2, (26.8-26)^2, (23.2-26)^2}{10} }$

$\cdot \ \cdot \ \cdot \sqrt{\frac{ ( 24.2-26)^2, (28.4-26)^2+( 25.0-26)^2+ (27.8-26)^2+( 27.3-26)^2+( 25.7-26)^2}{10} }$

$\sigma = 1.625$

The confidence level is given as 90% hence the level of significance is calculated as

$\alpha = 100 -90$

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$Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining the critical values of $\frac{\alpha }{2}$ instead of $\alpha$ is because we are considering two tails of the area under the normal curve