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Nady [450]
3 years ago
13

Can someone help me with this problem plz

Mathematics
1 answer:
BabaBlast [244]3 years ago
6 0

Answer:

4

Step-by-step explanation:

4 goes perfectly into 8 twice and 12 three times

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Factorize x^2/16+xy+4y^2​
lisov135 [29]

Answer:

\frac{x^2}{16} +xy+4y^2 can be factored out as: (\frac{x}{4} +2\,y)^2

Step-by-step explanation:

Recall the formula for the perfect square of a binomial :

(a+b)^2=a^2+2ab+b^2

Now, let's try to identify the values of a and b in the given trinomial.

Notice that the first term and the last term are perfect squares:

\frac{x^2}{16} = (\frac{x}{4} )^2\\4y^2=(2y)^2

so, we can investigate what the middle term would be considering our a=\frac{x}{4}, and b=2y:

2\,a\,b=2\,(\frac{x}{4}) \,(2\,y)=x\,y

Therefore, the calculated middle term agrees with the given middle term, so we can conclude that this trinomial is the perfect square of the binomial:

(\frac{x}{4} +2\,y)^2

4 0
3 years ago
Find the magnitude of AB.<br> A(-2, 6), B(1, 10)<br> O A 2<br> OB. ✔️15<br> O C.5<br> OD ✔️2
natita [175]

Answer:

C. 5

Step-by-step explanation:

Use the Distance Formula.

Substitute the values of x1 , y1 , x2 , and y2 .

|AB|² =|(1--2)²+(10-6)²|

|AB|² = |9+16|

|AB| = √ 25

|AB| =5

6 0
3 years ago
Jasmine has a hair ribbon collection. She ha 33 pink ribbon which is 25% of her collection. How many ribbon are in jasmines coll
jok3333 [9.3K]

Answer:

132 ribbons

Step-by-step explanation:

33/1 = 1/4

33 × 4 = 132

3 0
3 years ago
A painter leans a 15 ft ladder against a building. The base of the ladder is 6 ft from the building. To the nearest foot, how hi
stiv31 [10]
Using the Pythagoras theorem 

15^2 = x^2 + h^2   where h = height of ladder on the nuiding

h^2 = 15^2 - 6^2  =  189

 = 13.75 ft to nearest hundredth
3 0
3 years ago
Read 2 more answers
Elliot wants to compare the density of four objects to the density of water. Elliot knows that if an object sinks in water, it h
matrenka [14]

Answer: A would be the best answer

Step-by-step explanation:

3 0
3 years ago
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