Answer:
r = 11
L = 6
Step-by-step explanation:
7(6) = 42
5(11) = 55
42 + 55 = 97
Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
84%
Step-by-step explanation:
Completed passes: 21
total: 25
fraction: 21/25
21/25 x100
= 84
He has completed 84% of passes.
800 - 50 = 750
750 ÷ 5 =150
150 small vehicles were washed
