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BigorU [14]
3 years ago
11

PLZ HELP I NEED HELP REALLY HARD QUESTIONS THANKS SO MUCH!!!!! WILL BE GIVING BRAINLIEST AND FIVE STAR AND THANKS

Mathematics
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

1: 4

2: 2

3: 8

Step-by-step explanation:

You might be interested in
When graphing the inequality y ≤ 2x − 4, the boundary line needs to be graphed first. Which graph correctly shows the boundary l
Volgvan

Answer:

See Below

Step-by-step explanation:

The boundary line follows the graph of y = 2x - 4 because it represents the line of maximum or minimum values the graph could take. y = 2x - 4 has a y-intercept of -4 because it is in slope-intercept form. It also has a slope of 2, so to find another point on the line, you can go up two and right one. Also, this inequality has a solid line because it is "less than or equal to" and a solid line represents the values that equal.

6 0
3 years ago
Please Help me with this problem!!! ASAP
castortr0y [4]

The average rate of change is -5 per month

<h3>How to determine the average rate of change?</h3>

The interval is given as:

July to December

From the graph, we have:

July = 110

December = 30

The average rate of a function over the interval (a, b) is calculated as:

Rate = [f(b) - f(a)]/[b - a]

So, we have:

Rate = (30 - 110)/(December- July)

This gives

Rate = (30 - 110)/(12 - 7)

Evaluate

Rate = -16

Hence, the average rate of change is -5 per month

Read more about average rate of change at:

brainly.com/question/23715190

#SPJ1

6 0
2 years ago
How do I put y=90-15x in standard form
lisabon 2012 [21]

The standard form: Ax + By = C


y = 90 - 15x     <em>add 15x to both sides</em>

<h3>15x + y = 90</h3>
8 0
3 years ago
22. Solve 7x - 9 = 28+ 4(x - 1).<br> X=-3<br> X=3<br> x = 11<br> X=-11​
aleksley [76]

Answer:

c) x = 11

Step-by-step explanation:

Given equation: 7x - 9 = 28 + 4(x - 1)

<u><em>Steps:</em></u>

1. Distribute 4 through the parentheses:

7x - 9 = 28 + 4(x) + 4(-1)

7x - 9 = 28 + 4x - 4 [simplify]

7x - 9 = 24 + 4x

2. Subtract 4x from both sides:

7x - 4x - 9 = 24 + 4x - 4x

3x - 9 = 24

3. Add 9 to both sides:

3x - 9 + 9 = 24 + 9

3x = 33

4. Divide both sides by 3:

3x ÷ 3 = 33 ÷ 3

x = 11

5. Check your work:

7x - 9 = 28 + 4(x - 1) [substitute 11 for x]

7(11) - 9 = 28 + 4(11 - 1) [simplify]

77 - 9 = 28 + 4(10) [simplify]

68 = 28 + 40 [add]

68 = 68 ✔

Learn more here:

brainly.com/question/27844321

brainly.com/question/21222758

7 0
2 years ago
Read 2 more answers
Match the expressions with their equivalent simplified expressions.
Tasya [4]

Answer:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}


Step-by-step explanation:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}

\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}

\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}

\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}

\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}

\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}

Thus,

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}

3 0
3 years ago
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