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umka2103 [35]
3 years ago
6

I NEED HELP IN THIS QUESTION PLEASE

Mathematics
2 answers:
Elza [17]3 years ago
8 0
Techically bananas are nuts... 
almond37 [142]3 years ago
8 0
Answer J

4 Banana 
2 Apples 
6 Total Fruits

2/6 = 33%
4/6 = 67%

Original Ratio: 3/8 = 38% > 33%

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What methods do you know that can be used to solve a quadratic equation?
zhuklara [117]

Answer: If the quadratic equation has real, rational solutions, the quickest way to solve it is often to factorise into the form (px + q)(mx + n), where m, n, p and q are integers. This is especially true where the coefficient of x2 is 1.

Example 1 - Solve x2+7x+12=0

Step-by-step explanation:

that's the only one I remember

8 0
3 years ago
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Help pleaseeee!!!!!!
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Answer:

18. 46

19. 0.7

22. 4 3/4

23. 54.5

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27. 11.5

31. 15

etc.

Step-by-step explanation:

absolute value means that the sign in front of the # doesn't matter, you just have to look at the positive value, for example:

absolute value of 46  =  46

absolute value of - 36 = 36

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3 years ago
If AE=6x-55 and EC=3x-16, find DB. (Hint: Find x first and then substitute.)
erica [24]

<u>Given</u>:

Given that ABCD is a rectangle.

The diagonals of the rectangle are AC and DB.

The length of AE is (6x -55)

The length of EC is (3x - 16)

We need to determine the length of the diagonal DB.

<u>Value of x:</u>

The value of x can be determined by equating AE and EC

Thus, we have;

AE=EC

Substituting the values, we get;

6x-55=3x-16

3x-55=-16

       3x=39

         x=13

Thus, the value of x is 13.

<u>Length of AC:</u>

Length of AE = 6(13)-55=78-55=23

Length of EC = 3(13)-16=39-16=23

Thus, the length of AC can be determined by adding the lengths of AE and EC.

Thus, we have;

AC=AE+EC

AC=23+23

AC=46

Thus, the length of AC is 46.

<u>Length of DB:</u>

Since, the diagonals AC and DB are perpendicular to each other, then their lengths are congruent.

Hence, we have;

AC=DB

 46=DB

Thus, the length of DB is 46.

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3 years ago
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egoroff_w [7]

Answer:

6 hours...............

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In 2016, the city of Rio de Janeiro had a population density of 5377 people/km^2
Allushta [10]

Answer: The population density was 0.005377  people per square meter.

Step-by-step explanation:

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