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Lina20 [59]
3 years ago
10

Write the equation of a horizontal line that passes through the point (3, –3).

Mathematics
1 answer:
GREYUIT [131]3 years ago
6 0
D. y=-3
since this is a point and the line must be horizontal it is important to look at the y of the coordinate given. y=-3 then gives you the answer to your question since at x=3 the line would be vertical; at x=-3 the line would be going through quadrant two and three instead of quadrant one and four; and y=3 would be going through one and two instead of quadrant one and four.
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Somone explain this question to me ? And help me do it
vlabodo [156]
To answer your question the correct answer would be the last one because you would have to slide the triangle to the right to (1,1) and reflect it over the x-axis so that it became (-1,-1)

hope this helps
3 0
3 years ago
Find the distance between points A and C round to the nearest tenth.
Taya2010 [7]

Well the first thing that came to my mind was to do rise/run and doing that I got 6/5 which I added together to get 11 but since that's obviously not correct I assumed it was a little under so the answer I got was 7.8

Really hope this helps!

6 0
4 years ago
Combine like terms. (−2n−2)+(6+8m)+(8m+4n)
katrin2010 [14]

Answer:

16m + 2n + 4

Step-by-step explanation:

( −2n −2) + (6 + 8m) + (8m + 4n)

−2n + −2 + 6 + 8m + 8m + 4n

(8m + 8m) + ( −2n + 4n) + (−2 + 6)

16m + 2n + 4

7 0
3 years ago
The question is, "Find the volume of the bodies given in the figures below, which have a hole along their entire length." How do
aniked [119]

Answer:

1782 cm³

Step-by-step explanation:

First, you measure the volume of the cuboid as a whole which is length x breadth x height, 9 x 12 x 18 = 1944 cm³. Then measure the volume occupied by the space, 3 x 3 x 18 since the hole runs along the entire length = 162 cm³.

Then you subtract the volume occupied by the hole from the volume of the cuboid in total, 1944 - 162 = 1782 cm³

4 0
3 years ago
Solve 3x+2y=4 4x+3y=7 algebraically
Leona [35]
Step 1. Multiply first equation with -3 and the second one with 2. You'll get:
\left \{ {{-9x-6y=-12} \atop {8x+6y=14}} \right.

Step 2. Add both equations together. You'll get:
-x=2, which gives x = -2

Step 3. Replace x = -2 in the first equation and calculate y.
3(-2)+2y=4\\
y=\frac{4+6}{2}=5

The solution is: x=-2, y=5
8 0
3 years ago
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