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3 years ago

Need help not understanding it please thank you i appreciate it

Mathematics

1 answer:

saveliy_v [14]3 years ago

3 0

Angle ADG, angle BEH and angle CFI, all have two curves in their angles. Same number of curves are used to represent that their measure are equal.

So, m angle CFI = m angle ADG

So, m angle CFI = m angle ADG=> m angle CFI = 92°

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The functions f(x) and g(x) are defined below.

madam [21]

Uh im not sure completely but ill try my best to help.

f(x)=x-16/(x+10)(x-4)
g(x)=1/x+10

Now find a common denominator. (x+10)(x-4) is a good one.

x-16/(x+10)(x-4)+x-4/(x+10)(x-4)
2x-20/(x+10)(x-4)

So I think the answer is 2(x-10)/(x+10)(x-4) and x≠-10 and x≠4

Thats the most you can factor it. Don’t try to cancel out the (x-10) and the (x+10)

Brainliest my answer if it helped you out?

5 0

3 years ago

Read 2 more answers

Drag each tile to the correct box. Amanda, Derrick, and Todd attend the same high school. Each student works as the cashier one

wel

Answer:

Amanda > Todd > Derrick

Step-by-step explanation:

Amanda's IQR- 3.5

Derrick's IQR- 2

Todd's IQR- 3

4 0

3 years ago

Let f(x)= x^4 + ax^2 +b. The graph of f has a relative minimum at (0,1) and an inflection point when x=1. The values of a and b

Delvig [45]

$f(x)=x^4+ax^2+b\\f'(x)=4x^3+2ax\\f''(x)=12x^2+2a\\f''(1)=12(1)^2+2a\\12(1)=-2a\\a=-6\\\\f(x)=x^4-6x^2+b\\(1)=(0)^4-6(0)^2+b\\b=1$

a=-6
b=1

8 0

4 years ago

Which construction would you use to construct a right triangle with a compass and a straightedge? A. angle bisector B. copy an a

aleksandrvk [35]

D that’s the reason why it’s there

4 0

3 years ago

Using the transformation T: (x,y) —> (x+2, y+1), find the distance CB

pshichka [43]

Answer:

The distance between CB is $\sqrt[]{10}$

Step-by-step explanation:

Recall that the transformation T consists of a translation of 2 units to the right and 1 unit up. Then, T preserves distances(which means that it keeps distances between points the same as before applying the transformation). Then, distance CB is the sames as distance C'B'. We will use the distance formula: if we have points (x,y), (z,w) then the distance between them is given by

$\sqrt[]{(x-z)^2+(y-w)^2}$

In our case we have that C'=(0,3), B'=(3,4). Then, the distance between them is

$\sqrt[]{(3-0)^2+(4-3)^2}= \sqrt[]{10}$

5 0

3 years ago